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Accepted
Alex
Asked:2020-12-20 18:46:54 +0000 UTC2020-12-20 18:46:54 +0000 UTC

以json格式返回响应

  • 772

我有一个执行 POST 和 GET 的 RestController。我需要将返回的数据显示为 json。

public List<Persons> Names_List = new ArrayList<>();
@RestController
public class Post_Get {

public List<String> Names_List = new ArrayList<>();

@PostMapping(value = "api/names")
public String post (@RequestParam(value = "username", required = true, defaultValue = "None") String names) {
    Names_List.add(names);
        return " Saved:" + names;
}

@GetMapping(value = "api/names", produces = "application/json")
public String get(String result) {
        return "Names - " + Names_List.toString();
}

}

java

1 个回答

  1. Best Answer

    @PostMapping(value = "...", produces = MediaType.APPLICATION_JSON_VALUE). @GetMapping相似地。然后return-th 你返回一个普通的 POJO

    更新：你的代码看起来像这样（没有检查，也许有错字。但本质应该是清楚的）人

    public class Person {
    public String name; // Тут должен быть private, гет/сет методы и конструктор с именем. Пишу так с целью сокращения объема кода в примере.
}

    控制器：

    @RestController
public class MyController {

    private List<Person> persons = new ArrayList<>();

    @PostMapping(value = "api/persons", produces = MediaType.APPLICATION_JSON_VALUE)
    public Person post (@RequestParam("username") String name) {
        Person person = new Person(name);
        persons.add(person);
        return person;
    }

    @GetMapping(value = "api/persons", produces = MediaType.APPLICATION_JSON_VALUE)
    public List<Person> get() {
        return persons;
    }
}
    • 1

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