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Илья Бизунов
Asked:2020-04-24 02:39:09 +0000 UTC2020-04-24 02:39:09 +0000 UTC

无法以函数式风格重写代码

  • 772

出于纯粹的兴趣，我想以函数式风格实现这个命令式代码：

const _createArrayFromGroupObject = (groupObject) => {
  if (Array.isArray(groupObject))
    return groupObject

  const array = []
  for (const groupName in groupObject) {
    array.push([groupName, createArrayFromGroupObject(groupObject[groupName])])
  }
  return array
}

我试图这样做，但我遇到了堆栈溢出，我不明白问题是什么：

const objToArray = (groupObj) => 
  Object.keys(groupObj).reduce((arr, key) => [...arr, [key, objToArray(groupObj[key])]], [])

const createArrayFromGroupObject = (groupObj) => 
  Array.isArray(groupObj) ? groupObj : objToArray(groupObj)

沙盒：

const objToArray = (groupObj) => 
  Object.keys(groupObj).reduce((arr, key) => [...arr, [key, objToArray(groupObj[key])]], [])

const createArrayFromGroupObject = (groupObj) => 
  Array.isArray(groupObj) ? groupObj : objToArray(groupObj)

const _createArrayFromGroupObject = (groupObject) => {
	if (Array.isArray(groupObject))
  	return groupObject
  
  const array = []
  for (const groupName in groupObject) {
  	array.push([groupName, createArrayFromGroupObject(groupObject[groupName])])
  }
  return array
}

const groupObject = {"teacher":{"Peter":{"20":{"married":[{"name":"Peter","profession":"teacher","age":20,"maritalStatus":"married"},{"name":"Peter","profession":"teacher","age":20,"maritalStatus":"married"}]}},"Michael":{"50":{"single":[{"name":"Michael","profession":"teacher","age":50,"maritalStatus":"single"}]}}},"scientific":{"Anna":{"20":{"married":[{"name":"Anna","profession":"scientific","age":20,"maritalStatus":"married"}],"single":[{"name":"Anna","profession":"scientific","age":20,"maritalStatus":"single"}]}},"Rose":{"50":{"married":[{"name":"Rose","profession":"scientific","age":50,"maritalStatus":"married"}]}}},"politician":{"Anna":{"50":{"married":[{"name":"Anna","profession":"politician","age":50,"maritalStatus":"married"}]}}}}

console.log(_createArrayFromGroupObject(groupObject))
/* console.log(createArrayFromGroupObject(groupObject)) */

javascript

1 个回答

  1. Best Answer

    var k1 = Object.keys("0");
console.log("k1:", k1);
k1.forEach(el => console.log("el:", Object.keys(el)));

    在这里停止递归的条件是什么？

    • 1

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