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问题[tkinter]

Martin Hope
Владимир Лунёв
Asked: 2024-09-20 12:57:36 +0000 UTC
  • 5

告诉我如何确保当您在 Combobox tkinter 中选择一个值时，相应的信息会插入到条目小部件中？例如，有一个组合框和一个条目。组合框包含：“1”和“2”。如何确保当选择“1”时，值“红色”被插入到输入字段中，当选择“蓝色”时，值被插入到输入字段中。我将不胜感激任何帮助。

tkinter
Martin Hope
Furui Kenshi
Asked: 2023-12-18 23:49:02 +0000 UTC
  • 5

我正在尝试编写一个简单的转换器，它接受条目条目编号，当您单击计算按钮时，它会使用公式进行计算。如果没有 get，它不会转换为 int，但是一旦我绑定 get，所有输入字段都会从程序窗口中消失。有谁对如何克服这个有任何想法？

from tkinter import *
from tkinter import ttk

root = Tk()
root.title("Конвертор")
root.geometry("700x600")


class Window(Tk):
    def __init__(self):
        super().__init__()


def new_window():
    window = Tk()
    window.title("Листы в киллограммы")
    window.geometry("700x600")

    label0 = ttk.Label(window, text="Листы в кг.")
    label0.pack(anchor="center", padx=20, pady=10)

    label1 = ttk.Label(window, text="Ширина листа в мм. : ")
    label1.pack(anchor="center", padx=20, pady=10)

    entry_width = ttk.Entry(window)
    entry_width.pack(anchor="center", padx=20, pady=10)
    width = entry_width.get()
    int_width = int(width)

    label2 = ttk.Label(window, text="Длинна листа в мм. : ")
    label2.pack(anchor="center", padx=20, pady=10)

    entry_height = ttk.Entry(window)
    entry_height.pack(anchor="center", padx=20, pady=10)
    height = entry_height.get()
    int_height = int(height)

    label3 = ttk.Label(window, text="Масса листа в граммах : ")
    label3.pack(anchor="center", padx=20, pady=10)

    entry_mass = ttk.Entry(window)
    entry_mass.pack(anchor="center", padx=20, pady=10)
    mass = entry_mass.get()
    int_mass = int(mass)

    label4 = ttk.Label(window, text="Количество листов в шт. : ")
    label4.pack(anchor="center", padx=20, pady=10)

    entry_sheets = ttk.Entry(window)
    entry_sheets.pack(anchor="center", padx=20, pady=10)
    sheet = entry_sheets.get()
    int_sheets = int(sheet)

    label5 = ttk.Label(window, text="ИТОГО")
    label5.pack(anchor="center", padx=20, pady=10)

    def calc_1():
        answer = int_width * int_height * int_mass * int_sheets
        label5.config(text=answer)

    btn_calculated = ttk.Button(window, text="Рассчет", command=calc_1)
    btn_calculated.pack(anchor="center", padx=20, pady=10)


btn_win1 = ttk.Button(text="Листы в киллограммы", command=new_window)
btn_win1.pack(anchor="center", padx=20, pady=10)

root.mainloop()
tkinter
Martin Hope
Аркадий Вартанян
Asked: 2022-08-16 20:23:05 +0000 UTC
  • 1

我无法在窗口上设置为背景的图像上叠加标题。如果删除背景，则会出现铭文和输入字段。并且还显示没有铭文的背景。

错误：_tkinter.TclError: cannot use geometry manager pack inside 。已经有网格管理的奴隶

from tkinter import messagebox

root=Tk() #создаем окно
root.title('Авторизация')# Заголовок окна
root.geometry('900x700')# Размеры окна
root.resizable(width=TRUE, height=TRUE)# Если надо будет ограничить растяжение.
root['bg']='gold'# цвет окна внутри
root.image=PhotoImage(file="Book.png.png")
bg_logo=Label(root, image=root.image)
bg_logo.grid(row=0, column=0)



def registration():
    text=Label(text='Для входа в систему-зарегистритуйтесь!', font='Arial 30', bg='gold', fg='black')
    text.pack()
    text_firstname=Label(text='Введите ваше имя:', font='Arial 18', bg='gold', fg='black', padx=30)
    text_firstname.pack()
    register_lodin = Entry()
    register_lodin.pack()
    text_lastname=Label(text='Введите вашу фамилию:', font='Arial 18', bg='gold', fg='black', padx=30)
    text_lastname.pack()
    register_lodin = Entry()
    register_lodin.pack()
    text_patronymic = Label(text='Введите ваше отчество:', font='Arial 18', bg='gold', fg='black', padx=30)
    text_patronymic.pack()
    register_lodin = Entry()
    register_lodin.pack()
    text_log = Label(text='Введите логин ниже:', font='Arial 18', bg='gold', fg='black', padx=30)
    text_log.pack()
    register_log = Entry()
    register_log.pack()
    text_password = Label(text='Придумайте пароль:', font='Arial 18', bg='gold', fg='black', padx=30)
    text_password.pack()
    register_password = Entry()
    register_password.pack()
    text_repeatpassword = Label(text='Повторите пароль:', font='Arial 18', bg='gold', fg='black', padx=30)
    text_repeatpassword.pack()
    register_repeatpassword = Entry(show='*')
    register_repeatpassword.pack()





registration()


root.mainloop()
python tkinter
Martin Hope
Jabrail
Asked: 2022-08-06 23:34:02 +0000 UTC
  • 0

这是代码：

from tkinter import *

window = Tk()
window.geometry('270x450')

button_1 = Button(text='Часы', width=10, height=5, font=('Roman 10'))
button_1.place(x=50, y=50)

button_2 = Button(text='Календарь', width=12, height=6, font=('Roman 8'))
button_2.place(x=150, y=50)

button_3 = Button(text='Настройки', width=10, height=5, font=('Roman 9'))
button_3.place(x=50, y=150)

button_4 = Button(text='Игра', width=10, height=5, font=('Roman 10'))
button_4.place(x=150, y=150)

window.mainloop()

这是按钮应该打开的应用程序代码：

import tkinter
from tkinter import *
from datetime import datetime

root = tkinter.Tk()
root.title("Часы")
a = Label(root, font=("Gabriola", 20))


def update_time():
    root.geometry('270x450+{}+{}'.format(500, 400))
    a.config(text=f"{datetime.now():%H:%M:%S}")
    root.after(100, update_time)  # Запланировать выполнение этой же функции через 100 миллисекунд

a = Label(root, font=("helvetica", 40))
a.place(relx=0.5, rely=0.5, anchor=CENTER)
update_time()
root.mainloop()
python tkinter
Martin Hope
Jabrail
Asked: 2022-08-06 20:26:29 +0000 UTC
  • 1

我怎样才能使当您在搜索栏中输入“乌龟”一词并按下按钮时，笔会变成乌龟？

这是代码：

from tkinter import *
from turtle import *

pensize(4)
left(90)
shape("square")
color('#717171')
setup(550, 550)

def p():
    if entry_1 == 'Черепаха':
        shape('turtle')

btn_ton = Button(height=2, width=4, bg='#717171', command=p, text='↑', fg='white')
btn_ton.place(x=505, y=507)

entry_1 = Entry(width=50, font=('Gabriola 17'))
entry_1.pack(side=TOP)

done()
python tkinter