qwerty ytrewq's questions

use std::collections::HashMap;

pub fn frequency(input: &[&str], worker_count: usize) -> HashMap<char, usize> {
    let (tx, rx) = std::sync::mpsc::channel();

    let mut hndls = Vec::new();
    {
        // вычисляем количество потоков и размер порции
        let mut portion = 10; //минимальная порция
        let len = input.len();
        let mut cnt = (len as f64 / portion as f64 + 0.5) as usize;
        cnt = if cnt > worker_count {cnt} else {worker_count};
        portion = (len as f64 / cnt as f64 + 0.5) as usize;

        for (i, chank) in input.chunks(portion).enumerate() {
            let tx_local = tx.clone();
            let chank_local = chank.clone();  

            let handl = std::thread::spawn(move || {
                let mut mp_local = HashMap::new();

                //mp_local.insert('a', 1);
                for s in chank_local {
                    for ch in s.to_lowercase().chars() {
                        if let Some(val) = mp_local.get_mut(&ch) {
                            *val += 1;
                        } else {
                            mp_local.insert(ch, 1);
                        }
                    }
                }

                if let Err(e) = tx_local.send(mp_local) {
                    eprintln!("Ошибка записи в канал потоком {i}: {e}");
                }
            });

            hndls.push(handl);
        }
    }
    
    drop(tx);

    let mut mp = HashMap::new();
    for mp_local in rx {
        for (k,v) in mp_local {
            if let Some(val) = mp.get_mut(&k) {
                *val += v;
            } else {
                mp.insert(k, v);
            }
        }
    }

    for handl in hndls {
        handl.join().unwrap();
    }

    mp
}

错误：

error[E0521]: borrowed data escapes outside of function
  --> src/lib.rs:19:25
   |
3  |   pub fn frequency(input: &[&str], worker_count: usize) -> HashMap<char, usize> {
   |                    -----  - let's call the lifetime of this reference `'1`
   |                    |
   |                    `input` is a reference that is only valid in the function body
...
19 |               let handl = std::thread::spawn(move || {
   |  _________________________^
20 | |                 let mut mp_local = HashMap::new();
21 | |
22 | |                 //mp_local.insert('a', 1);
...  |
35 | |                 }
36 | |             });
   | |              ^
   | |              |
   | |______________`input` escapes the function body here
   |                argument requires that `'1` must outlive `'static`

error[E0521]: borrowed data escapes outside of function
  --> src/lib.rs:19:25
   |
3  |   pub fn frequency(input: &[&str], worker_count: usize) -> HashMap<char, usize> {
   |                    -----    - let's call the lifetime of this reference `'2`
   |                    |
   |                    `input` is a reference that is only valid in the function body
...
19 |               let handl = std::thread::spawn(move || {
   |  _________________________^
20 | |                 let mut mp_local = HashMap::new();
21 | |
22 | |                 //mp_local.insert('a', 1);
...  |
35 | |                 }
36 | |             });
   | |              ^
   | |              |
   | |______________`input` escapes the function body here
   |                argument requires that `'2` must outlive `'static`

For more information about this error, try `rustc --explain E0521`.
error: could not compile `parallel-letter-frequency` (lib test) due to 2 previous errors
warning: build failed, waiting for other jobs to finish...
error: could not compile `parallel-letter-frequency` (lib) due to 2 previous errors

printf 不打印负数。参见示例：

    .model flat
includelib msvcrt.lib
printf proto c, :vararg

    .data
resp db 'k = %d',10,13,0
k   db ?   

    .code
public main
main proc
    mov k, -1
    invoke printf, addr resp, k

    xor eax, eax
    ret
main endp
end

结果是k = 255，不是k = -1 如何打印一个负数？

到目前为止，我已经这样做了：

movsx ebx, k
invoke printf, addr resp, ebx

    .model flat 
    .code
public main
main proc
    ; здесь все четко
    mov     eax, 4292870144
    lea     eax, [eax+4294951040+4294967168]    

        ; и здесь все без нареканий
    mov     ebx, 4292870144
    add     ebx, 4294951040
    add     ebx, 4294967168

        ; НО ЗДЕСЬ МОЙ РАЗУМ ОСТАВЛЯЕТ МЕНЯ
    mov     esi, 4292870144
    mov     ecx, 4294951040
    mov     edx, 4294967168
    lea     ecx, [esi+ecx+edx]  ; **!!!здесь ошибка!!!** ecx <> eax = ebx


    xor eax, eax
    ret
main endp
end 

为什么会有不同的答案？