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Moonwolf45's questions

Martin Hope
Moonwolf45
Asked: 2024-09-27 02:06:23 +0800 CST
  • 5

总的来说，几天前我在 laravel10 + vuejs3 上创建了一个应用程序。今天我写了一份授权说明并留下了请求，一切正常。安装扩展以使用jwt后，我将授权重写为：

public function login(LoginRequest $request): JsonResponse
{
    $credentials = $request->only('email', 'password');

    $token = Auth::attempt($credentials);
    if ($token === false) {
        return response()->json([
            'status' => 'error',
            'message' => 'Unauthorized',
        ], 401);
    }

    $user = Auth::user();
    return response()->json([
        'status' => 'success',
        'user' => $user,
        'authorisation' => [
            'token' => $token,
            'type' => 'bearer',
        ]
    ]);
}

答案开始下降，出现 500 错误， "Malformed UTF-8 characters, possibly incorrectly encoded" 错误本身指向这里。

file:"D:\\OpenServer\\domains\\my_project\\testLara\\vendor\\laravel\\framework\\src\\Illuminate\\Http\\JsonResponse.php"
line: 88

有谁知道如何解决这个问题？

php
Martin Hope
Moonwolf45
Asked: 2023-10-30 17:31:40 +0800 CST
  • 5

我有一个 laravel 项目，在兰花中有一个管理面板，我更改了授权，但遇到了问题。我需要在登录时收到特定错误，但该怎么做？代码如下所示：

public function login(Request $request)
{
    $credentials = $request->validate([
        'email' => ['required', 'email'],
        'password' => ['required', 'string'],
    ]);

    $auth = $this->guard->attempt([
        'email' => $credentials['email'],
        'password' => $credentials['password'],
        'status' => User::$status['active']
    ], $request->filled('remember'));

    if ($auth) {
        return $this->sendLoginResponse($request);
    }

    throw ValidationException::withMessages([
        'email' => __('The details you entered did not match our records. Please double-check and try again.'),
        'password' => __('auth.password'),
        'status' => __('auth.status')
    ]);
}

现在如果有任何错误，那么我会收到所有 3 个错误。如何使用 attemp 方法找出具体错误是什么？或者我需要以不同的方式授权吗？

php
Martin Hope
Moonwolf45
Asked: 2023-09-23 18:29:09 +0800 CST
  • 5

Laravel 8 上有一个项目，为管理面板安装了 Orchid，在一个页面上我将用户上传到 Excel 文件，此上传需要考虑已安装的过滤器。这就是我现在的文件的样子：

public function query(): iterable {
    return [
        'participant' => Profile::when(Auth::user()->organizer_id, function (Builder $query) {
            return $query->where('organizer_id', Auth::user()->organizer_id);
        })->filters()->defaultSort('id', 'desc')->paginate(),
    ];
}

public function commandBar(): iterable {
    return [
        Button::make('Выгрузить в Excel')
            ->method('export')
            ->icon('cloud-download'),
    ];
}

public function export(Request $request) {
    $profiles = Profile::when(Auth::user()->organizer_id, function (Builder $query) {
        return $query->where('organizer_id', Auth::user()->organizer_id);
    })->filters()->select('external_id', 'last_name', 'first_name', 'patronymic', 'phone', 'email', 'gender',
        'date_of_birth', 'status')->defaultSort('id', 'desc')->get();

    $fileArray = array_merge([['Внешний id', 'Фамилия', 'Имя', 'Отчество', 'Номер телефона',
        'Email', 'Пол', 'Дата рождения', 'Статус']], $profiles->toArray());

    $spreadsheet = new Spreadsheet();
    $activeWorksheet = $spreadsheet->getActiveSheet();
    $activeWorksheet->getStyle('A1:I' . count($fileArray))->getNumberFormat()
        ->setFormatCode(NumberFormat::FORMAT_TEXT);

    $widthColumn = '20';
    $activeWorksheet->getColumnDimension('A')->setWidth($widthColumn);
    $activeWorksheet->getColumnDimension('B')->setWidth($widthColumn);
    $activeWorksheet->getColumnDimension('C')->setWidth($widthColumn);
    $activeWorksheet->getColumnDimension('D')->setWidth($widthColumn);
    $activeWorksheet->getColumnDimension('E')->setWidth($widthColumn);
    $activeWorksheet->getColumnDimension('F')->setWidth($widthColumn);
    $activeWorksheet->getColumnDimension('G')->setWidth($widthColumn);
    $activeWorksheet->getColumnDimension('H')->setWidth($widthColumn);
    $activeWorksheet->getColumnDimension('I')->setWidth($widthColumn);

    $activeWorksheet->fromArray($fileArray);

    $writer = new Xlsx($spreadsheet);

    return response()->streamDownload(function () use ($writer) {
        $writer->save('php://output');
    }, 'profiles.xlsx', [
        'Content-Type: application/vnd.openxmlformats-officedocument.spreadsheetml.sheet',
        'Content-Disposition: attachment;filename="profiles.xlsx"',
        'Cache-Control: max-age=0',
        'Last-Modified: ' . gmdate('D, d M Y H:i:s') . ' GMT',
        'Cache-Control: cache, must-revalidate',
        'Pragma: public'
    ]);
}

这有效并卸载了用户，但我无法想象如何传递数据以供过滤器导出。$request 中没有过滤数据。我需要你的帮助。

php
Martin Hope
Moonwolf45
Asked: 2022-09-28 16:27:43 +0800 CST
  • 0

有一个在 vuejs 上生成的页面。有一个伪目录，每张卡片都有一个这样的 div：

<div class="b-catalog__select">
    <select class="b-select" name="" @change="setCurrentNominalForItem({id: item.id, val: $event.target})">
        <option :value="option.value" v-for="(option, index) in getNominals(item.id)" :key="'option_' + index">{{ option.label }}</option>
    </select>
</div>

b-catalog__select 块具有以下样式：

&__select {
  flex: 1 1 auto;
  position: relative;

  &::after {
    content: '\f107';
    border: 0;
    font: 800 32px 'Font Awesome';
    transform: none;
    transition: transform 0.1s linear;
    transform-origin: 50% 50%;
    color: #aaa;
    position: absolute;
    right: 0;
  }
}

一般来说，正如你从代码中看到的那样，我创建了一个穿过伪元素的箭头，一切都会好起来的，但是如果你按下它，它就不会按原样打开，因为 这是一个不同的元素。那么如何让它打开呢？最好不要将箭头创建为单独的组件。

vue.js
Martin Hope
Moonwolf45
Asked: 2022-09-08 17:49:50 +0800 CST
  • 0

一般来说，有这样一个问题，在一个在docker上工作的项目中，我写了一个通过composer下载插件的脚本文件，看起来是这样的：

docker exec -ti php sh -c "cd var/www/project/apps/tele2 && composer install"

一般来说，没什么复杂的，我们进入容器，将自己拖到所需的文件夹并下载指示的所有内容。问题本身是有很多图书馆，一段时间后我发现了一个错误。但是，如果您手动执行所有这些操作，则不会出现错误，并且所有内容都可以很好地下载。你怎么能解决这样一个奇怪的问题？

错误如下所示：

- Installing vlucas/phpdotenv (v2.6.9): Extracting archive
- Installing opis/closure (3.6.2): Extracting archive
- Installing yiisoft/yii2-debug (2.1.18): Extracting archive
- Installing phpspec/php-diff (v1.1.3): Extracting archive
- Installing yiisoft/yii2-gii (2.2.3): Extracting archive
37/75 [=============>--------------]  49%    Install of bower-asset/font-awesome failed
Install of mpdf/mpdf failed
Install of bower-asset/jquery-ui failed
Install of bower-asset/bootstrap failed
Install of phpoffice/phpspreadsheet failed
Install of goodby/csv failed
Install of imagine/imagine failed
Install of bower-asset/sweetalert failed
Install of symfony/process failed
The following exception is caused by a process timeout
Check https://getcomposer.org/doc/06-config.md#process-timeout for details

In Process.php line 1204:
                                                                                                                                                                                                                                    
The process "'/usr/bin/unzip' -qq '/var/www/project/apps/tele2/app/vendor/composer/tmp-a8ffef473a25eb18ded9c8fc075e9091' -d '/var/www/project/apps/tele2/app/vendor/composer/b231a75c'" exceeded the timeout of 300 seconds.          
                                                                                                                                                                                                                                    

install [--prefer-source] [--prefer-dist] [--prefer-install PREFER-INSTALL] [--dry-run] [--dev] [--no-suggest] [--no-dev] [--no-autoloader] [--no-progress] [--no-install] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--apcu-autoloader-prefix APCU-AUTOLOADER-PREFIX] [--ignore-platform-req IGNORE-PLATFORM-REQ] [--ignore-platform-reqs] [--] [<packages>...]
docker cmd
Martin Hope
Moonwolf45
Asked: 2022-08-28 20:53:30 +0800 CST
  • 0

一般来说，我在 yii2 上有一个项目，我在管理面板中编辑产品并且一切正常，然后我写下该人需要显示一条消息，即：

Yii::$app->session->setFlash('success', "Товар $model->title сохранен");

问题是由于某种原因，我必须在此之后刷新页面，以便所有保存的数据正确显示，但随后不再显示该消息。那么，这就是我如何让它在重启后出现？？

Вывод сообщения:

<?php if (Yii::$app->session->getFlash('message')): ?>
    <div class="flash">
        <div class="alert alert-success alert-dismissable">
            <button type="button" class="close" data-dismiss="alert" aria-hidden="true">×</button>
            <h4> <i class="icon fa fa-check"></i> <?= Yii::$app->session->getFlash('message') ?></h4>
        </div>
     </div>
 <?php endif ?>
php yii2
Martin Hope
Moonwolf45
Asked: 2022-08-13 22:15:47 +0800 CST
  • 0

一般来说，我在 vue 上有一个项目，在输出带有时区的数组之前，我对其进行排序。数组看起来像这样：

arrTimeZone:Array[415] {
  0:Object {
    text:"(+00:00) Абиджане, Кот-д'Ивуар"
    value:"Africa/Abidjan"
  },
  1:Object {
    text:"(+00:00) Аккра, Гана"
    value:"Africa/Accra"
  },
  ...

一般来说，从打印输出中可以看到，其中有 415 个，粗略地说，是 php.ini 中指定的所有区域。一般来说，排序后的数组是这样的，首先是+0，然后是+1，...，+12，最后是-0，-1等。

我是这样排序的：

timeZoneSort.sort(function (a, b) {
  if (a.text > b.text) {
    return 1
  }
  if (a.text < b.text) {
    return -1
  }
  return 0
});

正常的升序排序。问题是如何使缺点继续进行？这样数组以 -12 开始，以 +12 结束

javascript
Martin Hope
Moonwolf45
Asked: 2022-07-22 23:47:58 +0800 CST
  • 1

一般来说，vueJs上有一个项目，我正在尝试从父级调用子组件的方法，但是有些事情没有解决。这是父组件中的内容：

<modalWindow :dialog="openFilter" :maxWidth="'720px'">
  <filterComponent ref="filterData" @callUpdateChartAndDataGrid="updateChartAndDataGrid" @callCloseModal="closeModal"></filterComponent>
</modalWindow>

<script>
    import ModalWindow from '@/components/Other/ModalComponent';
    import FilterComponent from '@/components/Other/FilterComponent';

...
onFilter () {
  this.openFilter = !this.openFilter;

  this.$refs.filterData.checkAllBills()
  this.$refs.filterData.checkAllCategories()
  this.$refs.filterData.checkAllCurrencies()
  this.$refs.filterData.checkAllTypes()
},
...

嗯，在孩子身上肯定有这样的方法，但是我得到以下错误：

vue.runtime.esm.js?2b0e:1888 TypeError: Cannot read properties of undefined (reading 'checkAllBills')

请帮忙。

javascript
Martin Hope
Moonwolf45
Asked: 2022-06-22 23:43:13 +0800 CST
  • 1

一般来说，我正在用 VueJS 编写一个应用程序，我的代码中有这个东西：

<tbody v-if="currencies !== null && currenciesUser !== null">
  <tr v-for="currencyItem in currenciesUser" :key="currencyItem.id">
    <td>{{ $t(currencyItem.Name) }}</td>
    <td v-if="currencyItem.CharCode !== mainCurrency.CharCode && mainCurrency.CharCode === 'RUB'">
      {{ new Intl.NumberFormat(mainCurrency !== null ? mainCurrency.locale : 'ru-RU', { style: 'currency', currency: mainCurrency !== null ? mainCurrency.CharCode : 'RUB', minimumFractionDigits: 2, maximumFractionDigits: 2}).format(currencies.Valute[currencyItem.CharCode].Value / currencies.Valute[currencyItem.CharCode].Nominal) }}
    </td>
    <td v-else-if="currencyItem.CharCode !== mainCurrency.CharCode && mainCurrency.CharCode !== 'RUB'">
      {{ new Intl.NumberFormat(mainCurrency !== null ? mainCurrency.locale : 'ru-RU', { style: 'currency', currency: mainCurrency !== null ? mainCurrency.CharCode : 'RUB', minimumFractionDigits: 2, maximumFractionDigits: 2 }).format((currencies.Valute[currencyItem.CharCode].Value / currencies.Valute[currencyItem.CharCode].Nominal) * (currencies.Valute[mainCurrency.CharCode].Value / currencies.Valute[mainCurrency.CharCode].Nominal)) }}
    </td>
    <td>{{ $moment(currencies.PreviousDate).format('DD.MM.YYYY HH:mm') }}</td>
  </tr>
</tbody>

在脚本代码中：

computed: {
  currencies () {
    return this.$store.getters.currencies
  },
  currenciesUser () {
    return this.$store.getters.currenciesUser
  },
  mainCurrency () {
    return this.$store.getters.mainCurrency
  }
}

事实上，一切都应该工作，但由于某种原因，我发现了一个错误：

TypeError: Cannot read properties of undefined (reading 'Value')
at eval (CurrencyCard.vue?4fd3:100:1)
at Proxy.renderList (vue.runtime.esm.js?2b0e:2630:1)
at Proxy.render (CurrencyCard.vue?4fd3:40:1)
at VueComponent.Vue._render (vue.runtime.esm.js?2b0e:3548:1)
at VueComponent.updateComponent (vue.runtime.esm.js?2b0e:4066:1)
at Watcher.get (vue.runtime.esm.js?2b0e:4479:1)
at Watcher.run (vue.runtime.esm.js?2b0e:4554:1)
at flushSchedulerQueue (vue.runtime.esm.js?2b0e:4310:1)
at Array.eval (vue.runtime.esm.js?2b0e:1980:1)
at flushCallbacks (vue.runtime.esm.js?2b0e:1906:1)

虽然 vuex 有这个数组，而且所有的检查都是值得的，但是还是会出现错误。怎么解决？？

javascript
Martin Hope
Moonwolf45
Asked: 2022-06-05 00:16:21 +0800 CST
  • 1

一般来说，我在 vuejs 上编写应用程序时遇到了这样的问题，我无法正确地从变量中提取数据。

这是代码：

<tbody v-if="currencies !== null && currenciesUser !== null">
  <tr v-for="currencyItem in currenciesUser" :key="currencyItem.id">
    <td>{{ $t(currencyItem.Name) }}</td>
    <td v-if="currencyItem.CharCode === 'RUB'">
      {{ new Intl.NumberFormat('ru-RU', { style: 'currency', currency: 'RUB',
        minimumSignificantDigits: 3 }).format(1) }}
    </td>
    <td v-else>
      {{ new Intl.NumberFormat(currencyItem.locale, { style: 'currency', currency: currencyItem.CharCode, minimumSignificantDigits: 3 }).format(currencies.Valute.filter(item => item.CharCode === currencyItem.CharCode).Value) }}
    </td>
    <td>{{ $moment(currencies.Date).format('DD.MM.YYYY HH:mm') }}</td>
  </tr>
</tbody>

我得到这个是这样的：

computed: {
  currencies () {
    return this.$store.getters.currencies
  },
  currenciesUser () {
    return this.$store.getters.currenciesUser
  }
}

在启动时我得到这个：

TypeError: _vm.currencies.Valute.filter is not a function

因此，没有任何输出。怎么赢？？

javascript
Martin Hope
Moonwolf45
Asked: 2022-05-07 19:32:11 +0800 CST
  • 0

我有一个项目，我写了一个搜索来查找联系人，一般来说有一个问题，搜索通过代码、电话、电子邮件引导。我可以编写一个 sql 函数来搜索单个请求，但是有没有办法确定在哪个参数上找到匹配项，通过电话、电子邮件或代码？刚才我提出了 3 个请求，tk。考虑找到匹配的参数，然后我需要输出，即 如果是电话，则输出电话，电子邮件表示电子邮件等。

搜索代码如下所示：

public function searchContactByPhoneCodeEmailOrderId($search) {
    $search_condition = \cArray::stripQuotes([
        'code' => \cString::prepareSearchString($search),
        'email' => \cString::prepareSearchString($search),
        'phone' => $search
    ]);

    $type = 'code';
    $response_contact = cFactory::getDB()->getRows("
        SELECT TOP 15 
            ID_Code, 
            code, 
            ID_Contact
        FROM
            tblCode
        WHERE
            ID_Contact IS NOT NULL
            AND code LIKE '" . $search_condition['code'] . "%'
    ", __FILE__, __LINE__);

    if (empty($response_contact)) {
        $response_contact = cAuthorizationModel::model()->getContactByOldCode($search_condition['code']);
    }

    if (empty($response_contact) && cChecker::phone($search_condition['phone'])) {
        $type = 'phone';
        $response_contact = cFactory::getDB()->getRows("
        SELECT TOP 15 
            ID_Contact, 
            phone
        FROM
            tblContact
        WHERE
            phone LIKE '" . $search_condition['phone'] . "%'
    ", __FILE__, __LINE__);
    }
    ...
}

嗯，我觉得本质很清楚，就不写太多了。

sql
Martin Hope
Moonwolf45
Asked: 2022-04-30 13:54:39 +0800 CST
  • 0

如何使 sql 查询允许您按 id 部分搜索？

我有这样的代码：

return cFactory::getDB()->getRows("
        SELECT TOP 20
            ID_Order,
            ID_Contact
        FROM
            tblOrder
        WHERE
            ID_Contact IS NOT NULL
            AND ID_Order = ''
    ", __FILE__, __LINE__);

但是如果它只能用于字符串值，该怎么写WHERE呢？ID_Orderlike

sql
Martin Hope
Moonwolf45
Asked: 2022-07-22 17:23:52 +0800 CST
  • 0

一般来说，我有一个我在yii2中编写的api，我决定摆脱不必要的代码，如果在检查过程中出现错误则抛出异常，我这样做：

if ($ticket->tickets_left > $count_ticket) {
    $ticket->tickets_left -= $count_ticket;
    $hours = json_decode($ticket->schedule_minute);
    foreach ($hours as $hour) {
        if ($hour == (int)$order['hours']) {
            if ($hour->tickets_left > $count_ticket) {
                if ((int)$order['ticketsCount']['adults']) {
                    $total_price += ((int)$order['ticketsCount']['adults'] * $hour->price_adults);
                }
    
                if ((int)$order['ticketsCount']['students']) {
                    $total_price += ((int)$order['ticketsCount']['students'] * $hour->price_stud);
                }
    
                if ((int)$order['ticketsCount']['children']) {
                    $total_price += ((int)$order['ticketsCount']['kid'] * $hour->price_children);
                }
                $hour->tickets_left -= $count_ticket;
    
                foreach ($hour->minutes as $minute) {
                    if ($minute->minute == (int)$order['minutes']) {
                        if ($minute->count_ticket_left > $count_ticket) {
                            $minute->count_ticket_left -= $count_ticket;
                        } else {
                            return throw new UnprocessableEntityHttpException(Yii::t('app', 'Sorry, tickets for the selected time have run out'));
                        }
                    }
                }
            } else {
                return throw new UnprocessableEntityHttpException(Yii::t('app', 'Sorry, tickets for the selected time have run out'));
            }
        }
    }
} else {
    return throw new UnprocessableEntityHttpException(Yii::t('app', 'Sorry, tickets for the selected time have run out'));
}

就是这样，一切都应该工作，但这是我通过邮递员得到的回应：

ParseError: syntax error, unexpected &#039;throw&#039; (T_THROW), expecting &#039;;&#039; in 
D:\OpenServer\domains\iBrush\teleportAdmin\api\controllers\OrderController.php:90
Stack trace:
#0 [internal function]: yii\BaseYii::autoload()
#1 [internal function]: spl_autoload_call()
#2 D:\OpenServer\domains\iBrush\teleportAdmin\vendor\yiisoft\yii2\base\Module.php(643): class_exists()
#3 D:\OpenServer\domains\iBrush\teleportAdmin\vendor\yiisoft\yii2\base\Module.php(602): yii\base\Module-&gt;createControllerByID()
#4 D:\OpenServer\domains\iBrush\teleportAdmin\vendor\yiisoft\yii2\base\Module.php(594): yii\base\Module-&gt;createController()
#5 D:\OpenServer\domains\iBrush\teleportAdmin\vendor\yiisoft\yii2\base\Module.php(528): yii\base\Module-&gt;createController()
#6 D:\OpenServer\domains\iBrush\teleportAdmin\vendor\yiisoft\yii2\web\Application.php(104): yii\base\Module-&gt;runAction()
#7 D:\OpenServer\domains\iBrush\teleportAdmin\vendor\yiisoft\yii2\base\Application.php(392): yii\web\Application-&gt;handleRequest()
#8 D:\OpenServer\domains\iBrush\teleportAdmin\web\index.php(12): yii\base\Application-&gt;run()
#9 {main}

基本上，我需要你的帮助。

php
Martin Hope
Moonwolf45
Asked: 2022-07-21 00:47:11 +0800 CST
  • 0

一般来说，使用yii2的动态表单和多字段扩展，我将数据集存储在mysql中的json字段中，我为站点编写了一个api，我显示了所有这些东西，我格式化了数组，并尝试返回它，但是我有同样的 json 字符串，看起来像这样：

[
    {
        "hour": "14", 
        "minutes": [
            {"minute": "00", "count_ticket": 1, "count_ticket_left": 1}, 
            {"minute": "10", "count_ticket": 1, "count_ticket_left": 1}, 
            {"minute": "20", "count_ticket": 1, "count_ticket_left": 1}, 
            {"minute": "30", "count_ticket": 1, "count_ticket_left": 1}, 
            {"minute": "40", "count_ticket": 1, "count_ticket_left": 1}, 
            {"minute": "50", "count_ticket": 1, "count_ticket_left": 1}
        ], 
        "price_stud": "1", 
        "price_adults": "1", 
        "tickets_left": "6", 
        "count_tickets": "6", 
        "price_children": "1"
    }, {
        "hour": "15", 
        "minutes": [
            {"minute": "00", "count_ticket": 1, "count_ticket_left": 1}, 
            {"minute": "10", "count_ticket": 1, "count_ticket_left": 1}, 
            {"minute": "20", "count_ticket": 1, "count_ticket_left": 1}, 
            {"minute": "30", "count_ticket": 1, "count_ticket_left": 1}, 
            {"minute": "40", "count_ticket": 1, "count_ticket_left": 1}, 
            {"minute": "50", "count_ticket": 1, "count_ticket_left": 1}
        ], 
        "price_stud": "1", 
        "price_adults": "1", 
        "tickets_left": "6", 
        "count_tickets": "6", 
        "price_children": "1"
    }
]

一般来说，什么可以更简单，但由于某种原因，我被困在这一点上，我正试图像这样获得这个奇迹：

foreach ($scheduleTickets as $ticket) {
    $new_date_ticket = new DateTime($ticket['date']);
    $norm_date = $new_date_ticket->format('d.m.Y');
    if ((int)$ticket['status'] == Tickets::STATUS_ON) {
        $allowTickets[$norm_date] = [];
        $allowTickets[$norm_date]['tickets'] = (int)$ticket['tickets_left'];
        $allowTickets[$norm_date]['hours'] = [];
        if ((int)$ticket['tickets_left'] > 0) {
            $i = 0;
            Yii::info($ticket);
            Yii::info($ticket['schedule_minute']);
            foreach ($ticket['schedule_minute'] as $time_hour) {
                Yii::info($time_hour);
                $allowTickets[$norm_date]['hours'][$i]['value'] = (int)$time_hour->hour;
                $allowTickets[$norm_date]['hours'][$i]['label'] = (string)$time_hour->hour;
                $allowTickets[$norm_date]['hours'][$i]['tickets'] = $time_hour->tickets_left;
                $allowTickets[$norm_date]['hours'][$i]['price_children'] = $time_hour->price_children;
                $allowTickets[$norm_date]['hours'][$i]['price_stud'] = $time_hour->price_stud;
                $allowTickets[$norm_date]['hours'][$i]['price_adults'] = $time_hour->price_adults;
                $allowTickets[$norm_date]['hours'][$i]['minutes'] = [];
                if ((int)$time_hour->tickets_left > 0) {
                    $y = 0;
                    foreach ($time_hour['minutes'] as $time_minute) {
                        $allowTickets[$norm_date]['hours'][$i]['minutes'][$y]['value'] = (int)$time_minute->minute;
                        $allowTickets[$norm_date]['hours'][$i]['minutes'][$y]['label'] = (string)$time_minute->minute;
                        $allowTickets[$norm_date]['hours'][$i]['minutes'][$y]['tickets'] = $time_minute->count_ticket_left;
                        $y++;
                    }
                }
                $i++;
            }
        }
    }
}

一般来说，我需要你的帮助，如何访问这些数据？

php
Martin Hope
Moonwolf45
Asked: 2022-02-14 23:32:33 +0800 CST
  • 1

我有一个用 写的菜单vue，如下所示：

<router-link v-for="(item, i) in menu" :key="i" :to="item.path" custom v-slot="{ navigate }">
    <v-list-item @click="navigate" @keypress.enter="navigate" role="link">
        <v-list-item-icon>
            <v-icon>{{ item.icon }}</v-icon>
        </v-list-item-icon>

        <v-list-item-content>
            <v-list-item-title>{{ $t(item.name) }}</v-list-item-title>
        </v-list-item-content>
    </v-list-item>
</router-link>

我怎样才能使它立即拥有我要去的项目，嗯，更准确地说，当我浏览这些项目时，它们被突出显示，但是我通过从另一个模板重定向到第一个项目并且它没有突出显示. 一般来说，我该怎么做？

这是里面的内容menu：

data () {
  return {
    menu: [
      { path: '/', name: 'main.bill', icon: 'account_balance_wallet' },
      { path: '/history', name: 'main.history', icon: 'history' },
      { path: '/planning', name: 'main.planning', icon: 'business_center' },
      { path: '/records', name: 'main.recording', icon: 'add_box' },
      { path: '/settings', name: 'main.settings', icon: 'settings' }
    ],
  }
}
vue.js
Martin Hope
Moonwolf45
Asked: 2022-02-11 00:27:58 +0800 CST
  • 0

一般来说，我以这种方式向api发送数据：

axios.post(environment.url + '/api/v1/users/registration', payload, { headers }).then(res => {
    console.log(res);
}).catch(err => {
    console.log(err);
})

但是当尝试像这样从 yii2 中获取时：

$user['bodyParams'] = Yii::$app->request->getBodyParams();

我得到一个空数组，但我这样做是这样的：

$user['raw'] = Yii::$app->request->getRawBody();

然后我可以将数据作为字符串获取，但这不适合我。

如何通过 POST 正常获取数据？

php
Martin Hope
Moonwolf45
Asked: 2022-02-08 20:16:48 +0800 CST
  • 0

我正在 yii2 中编写一个 api 模块并使用子模块进行版本控制。问题是我无法访问子模块中的页面，我只是得到404。这就是我在配置中描述的方式：

'modules' => [
    'api' => [
        'basePath' => '@app/api',
        'class' => app\api\ApiModule::class,
        'modules' => [
            'v1' => [
                'basePath' => '@app/api/v1',
                'class' => app\api\v1\V1Module::class,
            ]
        ],
        'components' => [
            'request' => [
                'class' => 'yii\web\Request',
                'parsers' => [
                    'application/json' => 'yii\web\JsonParser',
                ],
                'enableCsrfValidation' => false,
                'enableCsrfCookie' => false,
            ],
            'response' => [
                'class' => 'yii\web\Response',
                'formatters' => [
                    \yii\web\Response::FORMAT_JSON => [
                        'class' => 'yii\web\JsonResponseFormatter',
                        'prettyPrint' => YII_DEBUG,
                        'encodeOptions' => JSON_UNESCAPED_SLASHES | JSON_UNESCAPED_UNICODE
                    ]
                ]
            ]
        ]
    ],
],
...
'urlManager' => [
        'enablePrettyUrl' => true,
        'enableStrictParsing' => true,
        'showScriptName' => false,
        'rules' => [
            ['class' => 'yii\rest\UrlRule', 'controller' => ['api/v1/user']],

            '/' => 'site/index',
        ],
    ],

需要你的帮助。

php
Martin Hope
Moonwolf45
Asked: 2021-10-26 21:32:33 +0800 CST
  • 2

一般来说，我在yii2上有一个项目，有一个多对多关系的类别，我写了一个小部件，可以选择它们并按应有的方式排列它们，我需要按字母顺序对所有类别进行排序，我做它是这样的：

protected function getTree () {
    $tree = [];
    foreach ($this->data as $id => &$node) {
        if ($node['category_id_1'] == 0) {
            $tree[$node['categoryId2']['id']] = &$node['categoryId2'];
        } else {
            $tree[$node['category_id_1']]['childs'][$node['categoryId2']['id']] = &$node['categoryId2'];
        }
    }

    uasort($tree, function ($a, $b) {
        $lower_a = mb_strtolower($a['name']);
        $lower_b = mb_strtolower($b['name']);

        if ($lower_a == $lower_b) {
            return 0;
        }
        return ($lower_a < $lower_b) ? -1 : 1;
    });
    for ($i = 0; $i < count($tree); $i++) {
        if (!empty($tree[$i]['childs'])) {
            uasort($tree[$i]['childs'], function ($a, $b) {
                $lower_a = mb_strtolower($a['name']);
                $lower_b = mb_strtolower($b['name']);

                if ($lower_a == $lower_b) {
                    return 0;
                }
                return ($lower_a < $lower_b) ? -1 : 1;
            });
        }
    }

    return $tree;
}

粗略地说，在我建立了一个类别树之后，我对它进行了排序，但我只对父类别进行了排序，出于某种原因，孩子们没有改变。需要帮忙。

php
Martin Hope
Moonwolf45
Asked: 2020-09-11 19:43:05 +0800 CST
  • 1

一般来说，我正在为 VK 开发一个机器人，因此有必要发送一个链接。在电报中，要发送链接，您需要启用它parse_mode，但我没有为 VKontakte 找到类似的东西，如果您只是插入链接，它将作为字符串发送。我使用扩展发送。LukasAndreano/VKBotAPI需要帮助，如何发送链接？

php
Martin Hope
Moonwolf45
Asked: 2020-09-08 20:56:22 +0800 CST
  • 0

我正在通过webhook一个项目为电报编写一个机器人yii2，我安装了插件aki/yii2-bot-telegram。纯文本发送正常，但是链接有问题。我创建这样的链接：

$text .= 'Ссылка на диалог: <a href="' . Yii::$app->params['baseUrl'] . '/#/dialogs/' . $dialog['id'] . '">' . Yii::$app->params['baseUrl'] . '/#/dialogs/' . $dialog['id'] . '</a>' . "\n";
$text .= 'Или отправьте ответ на это сообщение для ответа пользователю.';

我这样发送：

Yii::$app->telegram->sendMessage([
    'chat_id' => $chat_id,
    'text' => $text,
    'parse_mode' => 'HTML',
    'disable_web_page_preview' => true
]);

也试过发送到Markdown，自然是用他求链接的阵型。结果是一样的——纯文本来了。怎么修？

php