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jokop's questions

Martin Hope
jokop
Asked: 2020-01-17 23:23:49 +0800 CST
  • 1

我在建表的时候遇到了这样一个问题：所有的线都没有画到最后。是什么原因我无法理解。或许知道的人可以给点建议。编码：

 \begin{tabular}{|p{2.5cm}|p{2.5cm}|p{2.5cm}|p{1.5cm}|p{1.5cm}|}    
    \hline      
    \multirow{Сооружения} & \multicolumn{3}{|c|}{Размещение горных выработок} & \multirow{Глубина горных выработок}\\ 
    \cline{2-4}
    {}  & Расстояние по оси трассы, м &  \multicolumn{3}{|c|}{Расстояние    } & {}\\ \cline{3-4}
     {}  & {}  &  на поперечниках, м   &  между поперечниками, м  &   {}\\ \end{tabular}

这是表格的样子： 在此处输入图像描述

latex
Martin Hope
jokop
Asked: 2020-09-09 19:47:18 +0800 CST
  • 0

您需要在迭代过程中填写列表。假设一个循环

for x in range(6):
    a = x+1

添加到x 1，我希望将结果a写入列表，如下所示：[1,2,3,4,5,6,7]。你想在哪里改变？

cache = [[(0, 0), (1, 0), (2, 0)],
 [(0, 0), (1, 0), (0, 0)],
 [(0, 0), (1, 0), (1, 1)],
 [(0, 0), (1, 0), (1, -1)],
 [(0, 0), (-1, 0), (0, 0)],
 [(0, 0), (-1, 0), (-2, 0)],
 [(0, 0), (-1, 0), (-1, 1)],
 [(0, 0), (-1, 0), (-1, -1)],
 [(0, 0), (0, 1), (1, 1)],
 [(0, 0), (0, 1), (-1, 1)],
 [(0, 0), (0, 1), (0, 2)],
 [(0, 0), (0, 1), (0, 0)],
 [(0, 0), (0, -1), (1, -1)],
 [(0, 0), (0, -1), (-1, -1)],
 [(0, 0), (0, -1), (0, 0)],
 [(0, 0), (0, -1), (0, -2)]]
# Compute the average end-to-end distance of random walks of a given lengt
for x in range (len(cache)):
    iks = (j for i in map(lambda x: tuple(zip(*x))[0], cache) for j in i)
    y = (j for i in map(lambda x: tuple(zip(*x))[1], cache) for j in i)
    iks1 = list(iks)
    y1 = list(y)
    f = lambda iks1, n=3: [iks1[i:i+n] for i in range(0, len(iks1), n)]
    f = lambda y1, n=3: [y1[i:i+n] for i in range(0, len(y1), n)]
    iks_elem=f(iks1)
    y_elem = f(y1)
for f in range(len(iks_elem)):
    iks_max = max(iks_elem[f])
    y_max = max(y_elem[f])
    x1=0
    y1 = 0    
    r = lambda iks_max,y_max, y1, x1: [sqrt((iks_max-x1)**2 + (y_max-y1)**2)]
    ab = r(iks_max,y_max, y1, x1)
    print (ab)
python
Martin Hope
jokop
Asked: 2020-09-08 23:38:34 +0800 CST
  • 1

有一个循环，其中的cache值是从中选择的：

  cache = [[(0, 0), (1, 0), (2, 0)],
     [(0, 0), (1, 0), (0, 0)],
     [(0, 0), (1, 0), (1, 1)],
     [(0, 0), (1, 0), (1, -1)],
     [(0, 0), (-1, 0), (0, 0)],
     [(0, 0), (-1, 0), (-2, 0)],
     [(0, 0), (-1, 0), (-1, 1)],
     [(0, 0), (-1, 0), (-1, -1)],
     [(0, 0), (0, 1), (1, 1)],
     [(0, 0), (0, 1), (-1, 1)],
     [(0, 0), (0, 1), (0, 2)],
     [(0, 0), (0, 1), (0, 0)],
     [(0, 0), (0, -1), (1, -1)],
     [(0, 0), (0, -1), (-1, -1)],
     [(0, 0), (0, -1), (0, 0)],
     [(0, 0), (0, -1), (0, -2)]]

循环本身

for x in range (len(cache)):
    for e in range(len(cache[x])):
        q,z = cache[x][e]
        print(q)

如何从循环中每次迭代获得的 q 中获取列表？ map(int,str(q))不能应用，因为有负q

python