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主页 / user-347699

hzybodska's questions

Martin Hope
hzybodska
Asked: 2022-07-27 04:26:54 +0000 UTC

运行“npm run scss”后如何解决错误

  • -1

packege.json
{ "name": "task_wp", "version": "1.0.0", "description": "", "main": "index.js", "scripts": { "scss": "node -sass -watch scss -o css" }, "author": "", "license": "ISC", "dependencies": { "node-sass": "^7.0.1" } }

运行 npm run scss 后出现这样的冲突code: 'ERR_INVALID_ARG_TYPE' } npm ERR! code ELIFECYCLE npm ERR! errno 1 npm ERR! task_wp@1.0.0 scss:node-sass -watch scss -o css` npm ERR!退出状态 1 npm ERR!npm 错误!task_wp@1.0.0 scss 脚本失败。npm 错误!这可能不是 npm 的问题。上面可能有额外的日志输出。

npm 错误!可以在以下位置找到此运行的完整日志:npm ERR!C:\Users\hp\AppData\Roaming\npm-cache_logs\2022-05-27T21_00_11_150Z-debug.log ` 第二天无法解决。完全昏迷。

npm
  • 1 个回答
  • 61 Views
Martin Hope
hzybodska
Asked: 2020-09-20 02:53:54 +0000 UTC

如何正确显示元素的标题文本?

  • 0

对于 ul.list 中的每个 li.item,我需要找到元素的标题文本(h2 标记)和类别中的元素数量(嵌套在其中的所有 li 元素),并将其输出到控制台。例如,对于您获得的第一个类别:

类别:动物 项目数:4 类别:食物 项目数:3 这是我的控制台输出的:

(3)[“类别:动物元素数量:4”,“类别:动物元素数量:3”,“类别:动物元素数量:5”]

它计算类别中的元素数量对我来说是正常的,但标题只显示动物。请告诉我是什么问题)这是我的解决方案

'use strict';
const categoriesUl = Array.from(
    document.querySelectorAll("ul#categories>li.item")
  );
  console.log(`В списке ${categoriesUl.length} категории`);
  const categoriesList = Array.from(
    document.querySelectorAll("ul#categories li.item ul ")
  );
  const categoriesArr = [];
  categoriesList.forEach(element => {
    categoriesArr.push(
      `Категория: ${
        document.querySelector("h2").textContent
      } / Количество элементов: ${element.children.length}`
    );
  });
  console.log(categoriesArr);
<ul id="categories">
  <li class="item">
    <h2>Животные</h2>

    <ul>
      <li>Кот</li>
      <li>Хомяк</li>
      <li>Лошадь</li>
      <li>Попугай</li>
    </ul>
  </li>
  <li class="item">
    <h2>Продукты</h2>

    <ul>
      <li>Хлеб</li>
      <li>Петрушка</li>
      <li>Творог</li>
    </ul>
  </li>
  <li class="item">
    <h2>Технологии</h2>

    <ul>
      <li>HTML</li>
      <li>CSS</li>
      <li>JavaScript</li>
      <li>React</li>
      <li>Node</li>
    </ul>
  </li>
</ul>

javascript
  • 2 个回答
  • 10 Views
Martin Hope
hzybodska
Asked: 2020-08-28 22:17:43 +0000 UTC

如何获得一系列用户技能但同时不重复

  • 0

我想获得所有用户的所有技能(技能字段)的数组,同时不应该有重复的技能,它们应该按字母顺序排序。这是我在这种情况下想出的。

'use strict';
const users = [
  {
    id: '701b29c3-b35d-4cf1-a5f6-8b12b29a5081',
    name: 'Moore Hensley',
    email: 'moorehensley@indexia.com',
    eyeColor: 'blue',
    friends: ['Sharron Pace'],
    isActive: false,
    balance: 2811,
    skills: ['ipsum', 'lorem'],
    gender: 'male',
    age: 37,
  },
  {
    id: '7a3cbd18-57a1-4534-8e12-1caad921bda1',
    name: 'Sharlene Bush',
    email: 'sharlenebush@tubesys.com',
    eyeColor: 'blue',
    friends: ['Briana Decker', 'Sharron Pace'],
    isActive: true,
    balance: 3821,
    skills: ['tempor', 'mollit', 'commodo', 'veniam', 'laborum'],
    gender: 'female',
    age: 34,
  },
  {
    id: '88beb2f3-e4c2-49f3-a0a0-ecf957a95af3',
    name: 'Ross Vazquez',
    email: 'rossvazquez@xinware.com',
    eyeColor: 'green',
    friends: ['Marilyn Mcintosh', 'Padilla Garrison', 'Naomi Buckner'],
    isActive: false,
    balance: 3793,
    skills: ['nulla', 'anim', 'proident', 'ipsum', 'elit'],
    gender: 'male',
    age: 24,
  },
  {
    id: '249b6175-5c30-44c6-b154-f120923736f5',
    name: 'Elma Head',
    email: 'elmahead@omatom.com',
    eyeColor: 'green',
    friends: ['Goldie Gentry', 'Aisha Tran'],
    isActive: true,
    balance: 2278,
    skills: ['adipisicing', 'irure', 'velit'],
    gender: 'female',
    age: 21,
  },
 
  
 
  {
    id: 'e1bf46ab-7168-491e-925e-f01e21394812',
    name: 'Sheree Anthony',
    email: 'shereeanthony@kog.com',
    eyeColor: 'brown',
    friends: ['Goldie Gentry', 'Briana Decker'],
    isActive: true,
    balance: 2764,
    skills: ['lorem', 'veniam', 'culpa'],
    gender: 'female',
    age: 39,
  },
];
const getSortedUniqueSkills = users => {
  return users
    .sort((a, b) => a.skills.length === b.skills.length)
    .map(e => e.skills);
};

console.log(getSortedUniqueSkills(users));

我让它们重复,而不是按字母顺序排序。预期结果应该是

[ 'adipisicing', 'amet', 'anim', 'commodo', 'culpa', 'elit', 'ex', 'ipsum', 'irure', 'laborum', 'lorem', 'mollit', 'non', 'nostrud', 'nulla', 'proident', 'tempor', 'velit', 'veniam' ]

javascript
  • 2 个回答
  • 10 Views
Martin Hope
hzybodska
Asked: 2020-08-28 20:29:55 +0000 UTC

无法根据朋友的数量对对象数组的名称进行排序

  • 0

我不知道如何根据朋友的数量(朋友字段)正确地对人的姓名数组(姓名字段)进行排序。我正在使用排序方法。但它给了我一个对象数组。这是我的代码

'use strict';
const users = [
  {
    id: '701b29c3-b35d-4cf1-a5f6-8b12b29a5081',
    name: 'Moore Hensley',
    email: 'moorehensley@indexia.com',
    eyeColor: 'blue',
    friends: ['Sharron Pace'],
    isActive: false,
    balance: 2811,
    skills: ['ipsum', 'lorem'],
    gender: 'male',
    age: 37,
  },
  {
    id: '7a3cbd18-57a1-4534-8e12-1caad921bda1',
    name: 'Sharlene Bush',
    email: 'sharlenebush@tubesys.com',
    eyeColor: 'blue',
    friends: ['Briana Decker', 'Sharron Pace'],
    isActive: true,
    balance: 3821,
    skills: ['tempor', 'mollit', 'commodo', 'veniam', 'laborum'],
    gender: 'female',
    age: 34,
  },
  {
    id: '88beb2f3-e4c2-49f3-a0a0-ecf957a95af3',
    name: 'Ross Vazquez',
    email: 'rossvazquez@xinware.com',
    eyeColor: 'green',
    friends: ['Marilyn Mcintosh', 'Padilla Garrison', 'Naomi Buckner'],
    isActive: false,
    balance: 3793,
    skills: ['nulla', 'anim', 'proident', 'ipsum', 'elit'],
    gender: 'male',
    age: 24,
  },
  {
    id: '249b6175-5c30-44c6-b154-f120923736f5',
    name: 'Elma Head',
    email: 'elmahead@omatom.com',
    eyeColor: 'green',
    friends: ['Goldie Gentry', 'Aisha Tran'],
    isActive: true,
    balance: 2278,
    skills: ['adipisicing', 'irure', 'velit'],
    gender: 'female',
    age: 21,
  },
  {
    id: '334f8cb3-eb04-45e6-abf4-4935dd439b70',
    name: 'Carey Barr',
    email: 'careybarr@nurali.com',
    eyeColor: 'blue',
    friends: ['Jordan Sampson', 'Eddie Strong'],
    isActive: true,
    balance: 3951,
    skills: ['ex', 'culpa', 'nostrud'],
    gender: 'male',
    age: 27,
  },
  {
    guid: '150b00fb-dd82-427d-9faf-2879ea87c695',
    name: 'Blackburn Dotson',
    email: 'blackburndotson@furnigeer.com',
    eyeColor: 'brown',
    friends: ['Jacklyn Lucas', 'Linda Chapman'],
    isActive: false,
    balance: 1498,
    skills: ['non', 'amet', 'ipsum'],
    gender: 'male',
    age: 38,
  },
  {
    id: 'e1bf46ab-7168-491e-925e-f01e21394812',
    name: 'Sheree Anthony',
    email: 'shereeanthony@kog.com',
    eyeColor: 'brown',
    friends: ['Goldie Gentry', 'Briana Decker'],
    isActive: true,
    balance: 2764,
    skills: ['lorem', 'veniam', 'culpa'],
    gender: 'female',
    age: 39,
  },
];

const getNamesSortedByFriendsCount = users => {
  return users.sort((a, b) => a.name - b.friends);
};

console.log(getNamesSortedByFriendsCount(users));
看起来没什么复杂的,但是实现这个方法是行不通的

javascript
  • 1 个回答
  • 10 Views
Martin Hope
hzybodska
Asked: 2020-08-28 17:24:35 +0000 UTC

获取所有用户名的数组

  • 0

请告诉我我错在哪里,为什么无法获取所有用户的名称数组,这些用户的名称具有指定名称的朋友。

'use strict';
const users = [
  {
    id: '701b29c3-b35d-4cf1-a5f6-8b12b29a5081',
    name: 'Moore Hensley',
    email: 'moorehensley@indexia.com',
    eyeColor: 'blue',
    friends: ['Sharron Pace'],
    isActive: false,
    balance: 2811,
    skills: ['ipsum', 'lorem'],
    gender: 'male',
    age: 37,
  },
  {
    id: '7a3cbd18-57a1-4534-8e12-1caad921bda1',
    name: 'Sharlene Bush',
    email: 'sharlenebush@tubesys.com',
    eyeColor: 'blue',
    friends: ['Briana Decker', 'Sharron Pace'],
    isActive: true,
    balance: 3821,
    skills: ['tempor', 'mollit', 'commodo', 'veniam', 'laborum'],
    gender: 'female',
    age: 34,
  },
  {
    id: '88beb2f3-e4c2-49f3-a0a0-ecf957a95af3',
    name: 'Ross Vazquez',
    email: 'rossvazquez@xinware.com',
    eyeColor: 'green',
    friends: ['Marilyn Mcintosh', 'Padilla Garrison', 'Naomi Buckner'],
    isActive: false,
    balance: 3793,
    skills: ['nulla', 'anim', 'proident', 'ipsum', 'elit'],
    gender: 'male',
    age: 24,
  },
  {
    id: '249b6175-5c30-44c6-b154-f120923736f5',
    name: 'Elma Head',
    email: 'elmahead@omatom.com',
    eyeColor: 'green',
    friends: ['Goldie Gentry', 'Aisha Tran'],
    isActive: true,
    balance: 2278,
    skills: ['adipisicing', 'irure', 'velit'],
    gender: 'female',
    age: 21,
  },
  {
    id: '334f8cb3-eb04-45e6-abf4-4935dd439b70',
    name: 'Carey Barr',
    email: 'careybarr@nurali.com',
    eyeColor: 'blue',
    friends: ['Jordan Sampson', 'Eddie Strong'],
    isActive: true,
    balance: 3951,
    skills: ['ex', 'culpa', 'nostrud'],
    gender: 'male',
    age: 27,
  },
  {
    guid: '150b00fb-dd82-427d-9faf-2879ea87c695',
    name: 'Blackburn Dotson',
    email: 'blackburndotson@furnigeer.com',
    eyeColor: 'brown',
    friends: ['Jacklyn Lucas', 'Linda Chapman'],
    isActive: false,
    balance: 1498,
    skills: ['non', 'amet', 'ipsum'],
    gender: 'male',
    age: 38,
  },
  {
    id: 'e1bf46ab-7168-491e-925e-f01e21394812',
    name: 'Sheree Anthony',
    email: 'shereeanthony@kog.com',
    eyeColor: 'brown',
    friends: ['Goldie Gentry', 'Briana Decker'],
    isActive: true,
    balance: 2764,
    skills: ['lorem', 'veniam', 'culpa'],
    gender: 'female',
    age: 39,
  },
];
const getUsersWithFriend = (users, friendName) => {
  return users.filter(
    user => (user.name === friendName.toLowerCase().indexOf('')) !== -1,
  );
  //
};

console.log(getUsersWithFriend(users, 'Briana Decker')); // [ 'Sharlene Bush', 'Sheree Anthony' ]
console.log(getUsersWithFriend(users, 'Goldie Gentry')); // [ 'Elma Head', 'Sheree Anthony' ]

最终结果应该是这样的

 [ 'Sharlene Bush', 'Sheree Anthony' ]
 [ 'Elma Head', 'Sheree Anthony' ]
javascript
  • 1 个回答
  • 10 Views
Martin Hope
hzybodska
Asked: 2020-08-28 11:46:42 +0000 UTC

如何仅通过眼睛颜色获取对象数组?

  • 1

我有一个这样的对象数组

'use strict';
const users = [
  {
    id: '701b29c3-b35d-4cf1-a5f6-8b12b29a5081',
    name: 'Moore Hensley',
    email: 'moorehensley@indexia.com',
    eyeColor: 'blue',
    friends: ['Sharron Pace'],
    isActive: false,
    balance: 2811,
    skills: ['ipsum', 'lorem'],
    gender: 'male',
    age: 37,
  },
  {
    id: '7a3cbd18-57a1-4534-8e12-1caad921bda1',
    name: 'Sharlene Bush',
    email: 'sharlenebush@tubesys.com',
    eyeColor: 'blue',
    friends: ['Briana Decker', 'Sharron Pace'],
    isActive: true,
    balance: 3821,
    skills: ['tempor', 'mollit', 'commodo', 'veniam', 'laborum'],
    gender: 'female',
    age: 34,
  },
  {
    id: '88beb2f3-e4c2-49f3-a0a0-ecf957a95af3',
    name: 'Ross Vazquez',
    email: 'rossvazquez@xinware.com',
    eyeColor: 'green',
    friends: ['Marilyn Mcintosh', 'Padilla Garrison', 'Naomi Buckner'],
    isActive: false,
    balance: 3793,
    skills: ['nulla', 'anim', 'proident', 'ipsum', 'elit'],
    gender: 'male',
    age: 24,
  },
  {
    id: '249b6175-5c30-44c6-b154-f120923736f5',
    name: 'Elma Head',
    email: 'elmahead@omatom.com',
    eyeColor: 'green',
    friends: ['Goldie Gentry', 'Aisha Tran'],
    isActive: true,
    balance: 2278,
    skills: ['adipisicing', 'irure', 'velit'],
    gender: 'female',
    age: 21,
  },
  {
    id: '334f8cb3-eb04-45e6-abf4-4935dd439b70',
    name: 'Carey Barr',
    email: 'careybarr@nurali.com',
    eyeColor: 'blue',
    friends: ['Jordan Sampson', 'Eddie Strong'],
    isActive: true,
    balance: 3951,
    skills: ['ex', 'culpa', 'nostrud'],
    gender: 'male',
    age: 27,
  },
  {
    guid: '150b00fb-dd82-427d-9faf-2879ea87c695',
    name: 'Blackburn Dotson',
    email: 'blackburndotson@furnigeer.com',
    eyeColor: 'brown',
    friends: ['Jacklyn Lucas', 'Linda Chapman'],
    isActive: false,
    balance: 1498,
    skills: ['non', 'amet', 'ipsum'],
    gender: 'male',
    age: 38,
  },
  {
    id: 'e1bf46ab-7168-491e-925e-f01e21394812',
    name: 'Sheree Anthony',
    email: 'shereeanthony@kog.com',
    eyeColor: 'brown',
    friends: ['Goldie Gentry', 'Briana Decker'],
    isActive: true,
    balance: 2764,
    skills: ['lorem', 'veniam', 'culpa'],
    gender: 'female',
    age: 39,
  },
];
我需要通过眼睛颜色“蓝色”输入用户这是我的解决方案

'use strict';
const users = [
  {
    id: '701b29c3-b35d-4cf1-a5f6-8b12b29a5081',
    name: 'Moore Hensley',
    email: 'moorehensley@indexia.com',
    eyeColor: 'blue',
    friends: ['Sharron Pace'],
    isActive: false,
    balance: 2811,
    skills: ['ipsum', 'lorem'],
    gender: 'male',
    age: 37,
  },
  {
    id: '7a3cbd18-57a1-4534-8e12-1caad921bda1',
    name: 'Sharlene Bush',
    email: 'sharlenebush@tubesys.com',
    eyeColor: 'blue',
    friends: ['Briana Decker', 'Sharron Pace'],
    isActive: true,
    balance: 3821,
    skills: ['tempor', 'mollit', 'commodo', 'veniam', 'laborum'],
    gender: 'female',
    age: 34,
  },
  {
    id: '88beb2f3-e4c2-49f3-a0a0-ecf957a95af3',
    name: 'Ross Vazquez',
    email: 'rossvazquez@xinware.com',
    eyeColor: 'green',
    friends: ['Marilyn Mcintosh', 'Padilla Garrison', 'Naomi Buckner'],
    isActive: false,
    balance: 3793,
    skills: ['nulla', 'anim', 'proident', 'ipsum', 'elit'],
    gender: 'male',
    age: 24,
  },
  {
    id: '249b6175-5c30-44c6-b154-f120923736f5',
    name: 'Elma Head',
    email: 'elmahead@omatom.com',
    eyeColor: 'green',
    friends: ['Goldie Gentry', 'Aisha Tran'],
    isActive: true,
    balance: 2278,
    skills: ['adipisicing', 'irure', 'velit'],
    gender: 'female',
    age: 21,
  },
  {
    id: '334f8cb3-eb04-45e6-abf4-4935dd439b70',
    name: 'Carey Barr',
    email: 'careybarr@nurali.com',
    eyeColor: 'blue',
    friends: ['Jordan Sampson', 'Eddie Strong'],
    isActive: true,
    balance: 3951,
    skills: ['ex', 'culpa', 'nostrud'],
    gender: 'male',
    age: 27,
  },
  {
    guid: '150b00fb-dd82-427d-9faf-2879ea87c695',
    name: 'Blackburn Dotson',
    email: 'blackburndotson@furnigeer.com',
    eyeColor: 'brown',
    friends: ['Jacklyn Lucas', 'Linda Chapman'],
    isActive: false,
    balance: 1498,
    skills: ['non', 'amet', 'ipsum'],
    gender: 'male',
    age: 38,
  },
  {
    id: 'e1bf46ab-7168-491e-925e-f01e21394812',
    name: 'Sheree Anthony',
    email: 'shereeanthony@kog.com',
    eyeColor: 'brown',
    friends: ['Goldie Gentry', 'Briana Decker'],
    isActive: true,
    balance: 2764,
    skills: ['lorem', 'veniam', 'culpa'],
    gender: 'female',
    age: 39,
  },
];


const getUsersWithEyeColor = (users, color) => {
  return users.filter(color => color.eyeColor === 'blue');
};

console.log(getUsersWithEyeColor(users, 'blue'));
同时显示3个蓝眼睛的用户,

[
  {
    "id": "701b29c3-b35d-4cf1-a5f6-8b12b29a5081",
    "name": "Moore Hensley",
    "email": "moorehensley@indexia.com",
    "eyeColor": "blue",
    "friends": [
      "Sharron Pace"
    ],
    "isActive": false,
    "balance": 2811,
    "skills": [
      "ipsum",
      "lorem"
    ],
    "gender": "male",
    "age": 37
  },
  {
    "id": "7a3cbd18-57a1-4534-8e12-1caad921bda1",
    "name": "Sharlene Bush",
    "email": "sharlenebush@tubesys.com",
    "eyeColor": "blue",
    "friends": [
      "Briana Decker",
      "Sharron Pace"
    ],
    "isActive": true,
    "balance": 3821,
    "skills": [
      "tempor",
      "mollit",
      "commodo",
      "veniam",
      "laborum"
    ],
    "gender": "female",
    "age": 34
  },
  {
    "id": "334f8cb3-eb04-45e6-abf4-4935dd439b70",
    "name": "Carey Barr",
    "email": "careybarr@nurali.com",
    "eyeColor": "blue",
    "friends": [
      "Jordan Sampson",
      "Eddie Strong"
    ],
    "isActive": true,
    "balance": 3951,
    "skills": [
      "ex",
      "culpa",
      "nostrud"
    ],
    "gender": "male",
    "age": 27
  }
]

但参数完全不同,我只需要一个眼睛颜色的字段

javascript
  • 1 个回答
  • 10 Views
Martin Hope
hzybodska
Asked: 2020-08-19 19:52:41 +0000 UTC

静态方法[关闭]

  • 1
关闭。这个问题不可能给出客观的答案。目前不接受回复。

你想改进这个问题吗? 重新构建问题,以便可以根据事实和引用来回答。

3年前关闭。

改进问题

如何在构造函数之前或之后在类中正确编写静态方法?阿里有没有区别?

javascript
  • 1 个回答
  • 10 Views
Martin Hope
hzybodska
Asked: 2020-08-19 05:52:57 +0000 UTC

上课出错。使用 do..while [关闭]

  • 0
关闭 这个问题是题外话。目前不接受回复。

寻求调试帮助的问题(“为什么这段代码不起作用? ”)应该包括期望的行为、具体的问题或错误,以及在问题中重现它的最少代码。没有明确描述问题的问题对其他访问者毫无用处。请参阅如何创建一个最小的、独立的和可重现的示例。

3年前关闭。

改进问题

'use strict';
class Car {
  constructor(maxSpeed, speed, isOn, distance, price) {
    this.maxSpeed = maxSpeed;
    this.speed = speed;
    this.isOn = isOn;
    this.distance = distance;
    this.price = price;
  }

  static getSpecs(car) {
    // console.log(maxSpeed, speed, isOn, distance, price);

    return this.maxSpeed, this.speed, this.isOn, this.distance, this.price;
  }

  get turnOn() {
    return this.price;
  }

  set turnOn(price) {
    this.price = price;
  }

  /*
   * Добавь геттер и сеттер для свойства price,
   * который будет работать с свойством цены автомобиля.
   */

  /*
   * Добавь код для того чтобы завести автомобиль
   * Записывает в свойство isOn значение true
   */
  turnOn() {
    this.isOn = true;
  }

  /*
   * Добавь код для того чтобы заглушить автомобиль
   * Записывает в свойство isOn значение false,
   * и сбрасывает текущую скорость в 0
   */

  turnOff() {
    this.isOn = false;
    this.speed = 0;
  }
  /*
   * Добавялет к свойству speed полученное значение,
   * при условии что результирующая скорость
   * не больше чем значение свойства maxSpeed
   */
  accelerate(value) {
    // this.speed += value;
    // while (this.speed < this.maxSpeed) {
    //   // console.log('counter: ', counter);
    //   // this.speed += value;
    // }

    this.speed > this.maxSpeed;
    this.speed += value;
  }

  /*
   * Добавялет к свойству speed полученное значение,
   * при условии что результирующая скорость
   * не больше чем значение свойства maxSpeed
   */
  decelerate(value) {
    this.speed -= value;
    this.speed !== 0;
  }

  /*
   * Добавляет в поле distance киллометраж (hours * speed),
   * но только в том случае если машина заведена!
   */
  drive(hours) {
    this.distance = hours * speed;
  }
}
const mustang = new Car({ maxSpeed: 200, price: 2000 });

mustang.turnOn();
mustang.accelerate(50);
mustang.drive(2);

Car.getSpecs(mustang);
// maxSpeed: 200, speed: 50, isOn: true, distance: 100, price: 2000

mustang.decelerate(20);
mustang.drive(1);
mustang.turnOff();

Car.getSpecs(mustang);
// maxSpeed: 200, speed: 0, isOn: false, distance: 120, price: 2000

console.log(mustang.price); // 2000
mustang.price = 4000;
console.log(mustang.price); // 4000

javascript
  • 2 个回答
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