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Asyaakoda's questions

Martin Hope
Asyaakoda
Asked: 2020-03-22 01:15:56 +0800 CST
  • -1

程序输入几行文本和一个字符进行搜索。使用该函数strchr，程序可以确定该字符在字符串中出现的次数。

int main()
{
    int k = 0;
    char str[100];
    char* pch;
    printf("please input 1 line:");
    scanf("%s", str);
    int ch;
    scanf("%d", &ch);
    pch = strchr(str, ch);
    puts(str);
    if (pch == NULL)
        printf("symbol not found\n");
    else
    {
        printf("sumbol %c on place %d\n", ch, pch - str + 1);
        k++;
    }
    printf("k:%d", k);
    return 0;
}
c
Martin Hope
Asyaakoda
Asked: 2020-03-01 21:17:58 +0800 CST
  • -2

第二个问题：对于整数 N(1 ≤ N ≤ 26 )，如何以相反的顺序打印拉丁字母的最后 N 个小写字母（从字母“z”开始）？在功能税 3 中，您需要解决第一个问题和功能任务 4 - 第二个问题

void task1();
void task2();
void task3();
void task4();
void task5();
void task6();

void main(){
}

void task1(){
   char N;
   do {

      N=getch();
     printf ("\nN: ");
      putchar(N);


        } while (32<=N<=126);
        getch();
}

void task2(){
char C,V;
   char C;
   do {
V=C+1;
      C=getch();

      printf ("You enter %c. ASCII code = %d\n", C, (int)C);
        } while (C<V);
        do {
V=C-1;
      C=getch();

      printf ("You enter %c. ASCII code = %d\n", C, (int)C);
        } while (C>V);

}

void task3(){
char M[100]
printf("\nM:");
    scanf("%d",&n);
    for(int i = 0; i<=n-1; i++)
        scanf("%d",&M[i]);
        for(int i=0;i<10;i++){
            printf("firs 10 elements:%d",M[i]);
        }

}
void task4(){
}
c
Martin Hope
Asyaakoda
Asked: 2020-02-20 23:59:18 +0800 CST
  • -2
#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main(){
    int *aPtr,*jPtr,size,size2,k,min,i,j;
    printf("Please input number of elements for array X:");
    scanf("%d",&size);
    aPtr = (int*)calloc(size,sizeof(int));
    for(int i=0;i<size;i++) {
        scanf("%d",&aPtr[i]);
    }
    printf("Please input number of elements for array Y:");
    scanf("%d",&size2);
    jPtr=(int*)calloc(size2,sizeof(int));
    for(int j=0;j<size2;j++) {
        scanf("%d",&jPtr[j]);
    }
    min=0;
    for(j=0;j<size2;j++)
        if(jPtr[j]<jPtr[min])
            min=i;
    printf("minimal element of array Y=%i",jPtr[min]);
    //if (jPtr[min]=&aPtr[i])printf("%d",aPtr[i]);
    return 0;
}
c