that_drowning_man's questions

    int main()
{
    int a = 8;
    int b = 2;
    int c = 1;

    int dob = 0;
    int* pdob = &dob;

    int avg = 0;
    int* pavg = &avg;

    int min = 0;
    int* pmin = &min;



    int* pa = &a;
    int* pb = &b;
    int* pc = &c;

    *pdob = (*pa) * (*pb) * (*pc);
    cout <<"dob -> "<< *pdob << endl;

    *pavg = *pa + *pb + *pc / 2;
    cout <<"average -> "<< *pavg << endl;

    if (*pb < min)
    {
        min = *pb;
    }

    if (*pc < min)
    {
        min = *pc;
    }

    cout <<"min -> "<< *pmin << endl;

}

我不明白为什么 0 是最小值，这在这里可能不正确。

编写一个内置函数以将数字提高到指定的幂。度数和数字作为参数传递给函数

    void Fill(int arr[], const int size);
int Max(int arr[], const int size);
float AverageFunc(int arr[], const int size);



void PrintArray(int arr[], const int size);
int main()
{
    int const size = 10;
    int const size1 = 7;
    int arr [size];

    srand(time(0));

    Fill(arr, size);
    PrintArray(arr, size);


    cout <<"Average -> "<< AverageFunc(arr, size) << endl;
    cout <<"Max -> "<< Max(arr, size) << endl;

}

void Fill(int arr[], const int size)
{
    for (int i = 0; i < size; i++)
    {
        arr[i] = rand() % 33 - 12;
    }
}

int Max(int arr[], const int size)
{
    int max = 0;

    for (int i = 0; i < size; i++)
    {
        if (arr[i] > max)
        {
            max = arr[i];
        }
    }
    return max;
}

float AverageFunc(int arr[], const int size)
{
    int sum = 0;
    float average = 0;
    for (int i = 0; i < size; i++)
    {
        sum += arr[i];
    }
    average = float(sum / size);
    return average;
}

void PrintArray(int arr[], const int size)
{
    for (int i = 0; i < size; i++)
    {
        cout <<"["<<i<<"]"<<setw(2)<< arr[i] << endl;;
    }
    cout << endl;
}