Pomador's questions

请告诉我问题是什么，数组的CRC在分部分计数时不收敛，代码如下

     uint8_t arr[] =
  {
    0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA,
    0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB,
    0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC,
    0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD
  };

  uint32_t crc_check_sum = 0;

  crc_check_sum = CRC_Calc(arr, sizeof(arr), DEFAULT_INIT_VALUE_ENABLE);
  printf("________CRC_Calc: 0x%x\r\n", crc_check_sum);

  uint8_t arr_1[] = {0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA, 0xAA};
  uint8_t arr_2[] = {0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB, 0xBB};
  uint8_t arr_3[] = {0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC, 0xCC};
  uint8_t arr_4[] = {0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD, 0xDD};

  uint32_t div_crc = 0; 
  uint32_t temp_crc = 0; 

  div_crc = CRC_TEST_Calc(arr_1, sizeof(arr_1), 0xFFFFFFFFU);

  temp_crc = div_crc;
  div_crc = CRC_TEST_Calc(arr_2, sizeof(arr_2), temp_crc);

  temp_crc = div_crc;
  div_crc = CRC_TEST_Calc(arr_3, sizeof(arr_3), temp_crc);

  temp_crc = div_crc;
  div_crc = CRC_TEST_Calc(arr_4, sizeof(arr_4), temp_crc);

  temp_crc = div_crc;
  printf("temp_crc: 0x%x\r\n", temp_crc);
  
  temp_crc = ~div_crc;
  printf("~temp_crc: 0x%x\r\n", temp_crc); 

功能实现：

void CRC_TEST_Init(uint32_t initValue)
{
  crc_hcrc.Instance = CRC;
  __HAL_RCC_CRC_CLK_ENABLE();
  crc_hcrc.Init.DefaultPolynomialUse    = DEFAULT_POLYNOMIAL_ENABLE;
  crc_hcrc.Init.DefaultInitValueUse     = DEFAULT_INIT_VALUE_DISABLE;
  crc_hcrc.Init.InitValue               = initValue;
  crc_hcrc.Init.InputDataInversionMode  = CRC_INPUTDATA_INVERSION_BYTE;
  crc_hcrc.Init.OutputDataInversionMode = CRC_OUTPUTDATA_INVERSION_ENABLE;
  crc_hcrc.Init.CRCLength               = CRC_POLYLENGTH_32B;
  crc_hcrc.InputDataFormat              = CRC_INPUTDATA_FORMAT_BYTES;
  if (HAL_CRC_Init(&crc_hcrc) != HAL_OK)
  {
    Error_Handler();
  }
}

    
uint32_t CRC_TEST_Calc(uint8_t * data, uint32_t size, uint32_t initValue)
{
  CRC_TEST_Init(initValue);
  CRPT_CksumStart();

  uint32_t res = HAL_CRC_Calculate(&crc_hcrc, (uint32_t *)data, size);

  return res;
}

uint32_t CRC_Calc(uint8_t * data, uint32_t size, uint32_t initValue)
{
  CRC_TEST_Init(initValue);
  CRPT_CksumStart();

  uint32_t res = HAL_CRC_Calculate(&crc_hcrc, (uint32_t *)data, size);

  return ~res;
}

告诉我，如何在没有循环的情况下初始化动态数组？找到这种方式

int arr[] = {[0 ... 20] = 0xFF};

但我不知道如何将它应用于动态数组

我以这种方式将数组传递给函数，不是因为我非常喜欢它，而是因为它在任务中是必需的。

在函数中，数组变小了3个字节，告诉我是什么原因

#include <stdio.h>

char* foo(char* in)
{ 
    printf("%i\n", sizeof(in));  // 8 байт
}

int main()
{
    char message[11] = "hello world";
    printf("%i\n", sizeof(SIZE));    // 11 байт
    foo(message);

    return 0; 
}