в Гостях у Сурка's questions

我（有条件地）有一个变量text = "Hello"。

我需要这样做print("text World")：

我知道这样做是正确的print(text, " World")：但是我的函数有一个参数。

如何将变量推入字符串？

打开菜单时，脚本应该运行，但它没有运行。

hook.Add('c_menu','OpenMenu', function(ply)
   if SANDBOX:ContextMenuOpened() == true then
     CmdDerma() 
     print('Context menu is open')        
   end
end)

为什么管道在接触窗口的开头时不会移动到末端？

import pygame

pygame.init()

sc = pygame.display.set_mode((700,800))
pygame.display.set_caption("Flappy Bird")
FPS = 30
clock = pygame.time.Clock()

x = 350
y = 400

xOfDuct = 732
yOfDuct = 800 

flag = 0

def duct():
    ductOne_surf = pygame.image.load('trubaDown.png')
    ductOne_surf = pygame.transform.scale(ductOne_surf, (120,452))   
    ductOne_rect = ductOne_surf.get_rect(bottomright=(xOfDuct,yOfDuct))
    sc.blit(ductOne_surf,ductOne_rect)
def ductTwo():
    duct_surf = pygame.image.load('trubaUp.png')
    duct_surf = pygame.transform.scale(duct_surf, (120,452))
    duct_rect = duct_surf.get_rect(bottomright=(xOfDuct, yOfDuct - yOfDuct + 175))
    sc.blit(duct_surf,duct_rect)

while True:
    sc.fill((255,255,255))
    duct()
    ductTwo()
    pygame.draw.circle(sc, (255,255,0),(x,y),20)

    for i in pygame.event.get():
        if i.type == pygame.QUIT:
            exit()
    
    keys = pygame.key.get_pressed()     

    if keys[pygame.K_SPACE]: 
        flag = 0
        y-=15
    if xOfDuct == 0:
        xOfDuct = 700       
    flag+=2
    y+=flag     
    xOfDuct -= 10

    pygame.display.update()             
    clock.tick(FPS)     

我的程序垂直绘制线条并将它们按从低到高的顺序排列。为什么排序是一次发生而不是逐渐发生的？

import pygame

pygame.init()

sc = pygame.display.set_mode((1200,600))
FPS = 1
clock = pygame.time.Clock()

y = [230,240,270,210,300,220]

def draw(xOne,yOne,xTwo,yTwo,Width):
    pygame.draw.line(sc,(0,0,255),(xOne,yOne),(xTwo,yTwo), Width)

while True:
    sc.fill((255,255,255))
    draw(200,400,200,y[0],10)   
    draw(250,400,250,y[1],10)   
    draw(300,400,300,y[2],10)   
    draw(350,400,350,y[3],10)   
    draw(400,400,400,y[4],10)   
    draw(450,400,450,y[5],10)   

    for h in pygame.event.get():
        if h.type == pygame.QUIT:
            exit()
    for i in range(len(y)):

        for j in range(len(y) - i - 1):

            if y[j] < y[j+1]:
                y[j], y[j+1] = y[j+1], y[j]     


    pygame.display.update()             
    clock.tick(FPS)     

为什么，有了这个代码，船不会改变它的位置

import pygame

pygame.init()

sc = pygame.display.set_mode((1200, 1200))
clock = pygame.time.Clock()
FPS = 60

x = 600
y = 600

K = pygame

def SpaceShip(xShip, yShip):
    ship_surf = pygame.image.load('spaceShip.png')
    ship_rect = ship_surf.get_rect(bottomright=(xShip - 32, yShip - 32))
    ship_surf = pygame.transform.scale(ship_surf, (100,100))
    sc.blit(ship_surf, ship_rect)

pygame.display.update()

while True:
    sc.fill((0,0,0))
    SpaceShip(x, y)
    
    for i in pygame.event.get():
        if i.type == pygame.QUIT:
            exit()
    keys = pygame.key.get_pressed()
    
    if keys == K.K_LEFT:
        x -= 3
    elif keys == K.K_RIGHT:
        x += 3      

    pygame.display.update()     
    clock.tick(FPS)     

为什么在这段代码中，触摸线时圆圈不会停止？如果有人知道如何在接触地面时停下来，请写信。

import pygame

pygame.init()

FPS = 30
 
x = 300
y = 200

xL = 200
xL2 = 400
yL = 300

sc = pygame.display.set_mode((600, 400))
clock = pygame.time.Clock()
pygame.display.update()

speedDown = 0 

while True:
    sc.fill((255,255,255))

    clock.tick(FPS)

    pygame.draw.circle(sc,(0,0,255),(x,y), 20, 0)
    pygame.draw.line(sc,(0,0,0),(xL,yL),(xL2,yL),5)

    for i in pygame.event.get():
        if i.type == pygame.QUIT:
            exit()
 
    keys = pygame.key.get_pressed()
    
    if y == yL:
       speedDown = 0
       y += 5
    else:
       speedDown += 1
       y += speedDown  

    pygame.display.update()