Anton Kuznetsov's questions

有4个对象

public object ObjectGet = { get; set; }
public Object1TType Object1 = new Object1TType();
public Object2TType Object2 = new Object2TType();
public object Object3Set = new();
...
if ... => ObjectGet = new Object1TType(...)
else => ObjectGet = new Object2TType(...)

我知道代码本身可以有一个 Object3Set ：

if (ObjectGet is Object1TType)
{
    Object3Set = ObjectGet as Object1TType;
}
else if (ObjectGet is Object2TType)
{
    Object3Set = ObjectGet as Object2TType;
}

但是如何根据全局对象的类型将对象 Object3Set的类型更改为Object1TType或Object2TType，以便我可以访问Object3Set.Field（假设我知道在这个地方它是 100% Object1TType ）而无需在本地创建一个 Object3Set？

工作代码示例： 1.cs

namespace ObjectType
{
    public class Object1TType : ICloneable
    {
        public ulong Field { get; set; }
        public Object1TType()
        {
        }

        public Object1TType( ulong Field)
        {
            this.Field = Field;
        }
        public object Clone()
        {
            return new Object1TType(Field);
        }
    }

    public class Object2TType : ICloneable
    {
        public ulong Field { get; set; }
        public Object2TType()
        {
        }

        public Object2TType(ulong Field)
        {
            this.Field = Field;
        }
        public object Clone()
        {
            return new Object2TType(Field);
        }
    }

    public class Class1
    {
        public static object ObjectGet = new Object1TType();

        public static void Do()
        {
            ulong test = 123;
                ObjectGet = new Object2TType(test);
        }
    }
}

2.cs

namespace Code
{
    public class Main
    {
        public object ObjectGet = ObjectType.Class1.ObjectGet;
        public object Object3Set = new();

        public void Do()
        {
            ObjectType.Class1.Do();
            if (ObjectGet is ObjectType.Object1TType)
            {
                Object3Set = ObjectGet as ObjectType.Object1TType;
            }
            else if (ObjectGet is ObjectType.Object2TType)
            {
                Object3Set = ObjectGet as ObjectType.Object2TType;
            }

            Console.WriteLine(Object3Set.Field);
        }
    }
}

在这里我无法访问ObjectGet.Field和Object3Set.Field，为此我认为我需要对Object3Set做一些事情并使用它

有一个数据模型：

public class Item1
{
    public long Addr { get; set; }
    public long Pos { get; set; }
    public string Description { get; set; }
    public long Number { get; set; }
}

public class Item2
{
    public long Addr { get; set; }
    public string Description { get; set; }
    public ulong Pointer{ get; set; }
}

创建了 Item1 和 Item2：

var items1 = new Dictionary<ulong, Item1>();
items1.Add(id, new Item1
{
    Addr = Addr,
    Pos = Pos,
    Description = Description,
    Number = Number
    Pointer = Pointer
});

var items2 = new Dictionary<ulong, Item2>();
items1.Add(id, new Item2
{
    Addr = Addr,
    Description = Description,
    Pointer = Pointer
});

有一个itemPointers列表，其中包含items1中的匹配id和item2中的Pointer

列出 itemPointers = new();

如何创建这样的 itemPointers列表？

我试图玩itemPointers = items1.Select(e =>items2.ContainsKey(e.Pointer))，我知道在 items2.ContainsKey(e.Pointer) 的某个地方应该有 ForEach，但我不明白我在哪里知道我能做到

foreach (var id in items2)
{
    if (items1.ContainsKey(items2[id.Key].Pointer))
    {
        itemPointers.Add(id.Key);
    }
}

但似乎有一种更优雅（更快？）的方式来做到这一点。

有一个嵌套列表

public Dictionary<dynamic, Dictionary<string, dynamic>> Data = new();

以下数据被动态添加到其中：

Data .Add(ID, new Dictionary<string, dynamic> {
  { "Addr", Addr },
  { "Pos", Pos  },
  { "Description", Description },
  { "Number", Number  }
});

结果，我们得到一个近似列表：

Data["adx01"][{"Addr":5},{"Pos":100},{"Description":"Описание1"},{"Number":44}];
Data["vdx11"][{"Addr":2},{"Pos":45},{"Description":"Описание2"},{"Number":12}];
Data["ydx50"][{"Addr":3},{"Pos":67},{"Description":"Описание3"},{"Number":71}];
Data["zdx31"][{"Addr":10},{"Pos":9},{"Description":"Описание4"},{"Number":33}];

我需要按“数字”字段对其进行排序，使其看起来像这样：

Data["ydx50"][{"Addr":3},{"Pos":67},{"Description":"Описание3"},{"Number":71}];
Data["adx01"][{"Addr":5},{"Pos":100},{"Description":"Описание1"},{"Number":44}];
Data["zdx31"][{"Addr":10},{"Pos":9},{"Description":"Описание4"},{"Number":33}];
Data["vdx11"][{"Addr":2},{"Pos":45},{"Description":"Описание2"},{"Number":12}];

什么方法可以做到这一点？

答案：aepot：Data=Data.OrderBy(pair => (int)pair.Value["Number"]).ToDictionary(pair => pair.Key, pair => pair.Value)