主页 / user-613552

Алексей's questions

Martin Hope
Алексей
Asked: 2024-08-20 06:38:41 +0000 UTC
  • 7

有这么一段代码

a = "Apple<.3"
await bot.send_message(message.from_user.id,
                           f'Переменная a = <code>{a}</code>')

但 telegram 无法处理它并写入此错误。

 File "C:\Program Files\Python312\Lib\site-packages\aiogram\client\session\base.py", line 120, in check_response
    raise TelegramBadRequest(method=method, message=description)
aiogram.exceptions.TelegramBadRequest: Telegram server says - Bad Request: can't parse entities: Unsupported start tag ".3</code" at byte offset 81
python
Martin Hope
Алексей
Asked: 2024-08-20 05:43:58 +0000 UTC
  • 6

有这样一本词典

a = {1: ['Антон', 'Артем'], 2: ['Сергей']}

您需要通过从字典中写入数据来补充变量

с = "\n".join([f'{name} на {place}' for place, name in a.items()])

但输出带有括号

['Антон', 'Артем'] на 1
['Сергей'] на 2

但它需要像这样

Антон, Артем на 1
Сергей на 2

不再需要打印中解包的方法，就像使用[0]一样！

python
Martin Hope
Алексей
Asked: 2024-08-14 21:52:48 +0000 UTC
  • 7

需要从这

name1212 | (0:55)
name12122 | (0:43)
name45152 | (0:38)
name121212 | (0:25)
name11212 | (0:18)
name1123 | (0:06)
name123 | (0:02)
name1232 | (0:01)

是吗

name1212    | (0:55)
name12122   | (0:43)
name45152   | (0:38)
name121212  | (0:25)
name11212   | (0:18)
name1123    | (0:06)
name123     | (0:02)
name1232    | (0:01)

但问题是，为了接收玩家和时间，我将其作为一个单独的函数来执行，并且我不明白如何像其他人一样实现它。

获取玩家和时间的代码：

    def get_players_with_time(server_ip):
        ip = str(server_ip.split(',')[0])
        port = int(server_ip.split(',')[1])
        address = (f"{ip}", port)

        get_players = a2s.players(address)
        players = "\n".join(player.name + ' | (' + str(datetime.timedelta(seconds=player.duration))[0:4] + ')' for player in get_players)
        return players
python
Martin Hope
Алексей
Asked: 2024-08-13 02:41:49 +0000 UTC
  • 6

数据库中有这样的动态内联按钮代码

def FindPlayer(user_id):
    Find_Players = BotDB.get_find_users(user_id)
    kb = InlineKeyboardBuilder()
    for find_user in Find_Players:
        kb.button(text=f'{Find_Players[0][0]}', callback_data=f'findPlayer|{Find_Players[0][0]}')
    kb.adjust(1)
    return kb.as_markup()

一切都很好。按钮是根据数据库中的编号创建的，但名称来自第一行

在此输入图像描述

在此输入图像描述

通过 user_id 查找 find_user 中所有行的代码

    def get_find_users(self, user_id):
        result = self.cursor.execute("SELECT `find_user` FROM `players` WHERE `user_id` = ?", (user_id,))
        return result.fetchall()

需要注意的是name1不能重复，而应该根据他们的名字。

我认为这个错误是由于[0][0]造成的，但我不知道如何智能地输出它。

python
Martin Hope
Алексей
Asked: 2024-08-08 21:10:32 +0000 UTC
  • 5

您需要从运算符获取一个变量并使用它继续执行函数

async def get_info(call: CallbackQuery, bot: Bot):

    call_number = int(call.data.replace('server', '', 1).split('_')[1])
    print(call_number)

    global info
    global player_names
    global ip
    global port
    global fh_type

    if call_number == '1':
        server = server_1_ip
        return server

    elif call_number == '2':
        server = server_2_ip
        return server

    elif call_number == '3':
        server = server_3_ip
        return server

    elif call_number == '4':
        server = server_4_ip
        return server

    elif call_number == '5':
        server = server_5_ip
        return server

    elif call_number == '6':
        server = server_6_ip
        return server

    elif call_number == '7':
        server = server_7_ip
        return server

    elif call_number == '8':
        server = server_8_ip
        return server

    ip = str(server.split(',')[0])
    port = int(server.split(',')[1])
    fh_type = server.split(',')[2]

    address = (f"{ip}", port)
    print(address)

    info = a2s.info(address)
    players = a2s.players(address)

    print(info)
    print(players)

如果需要的话，上面列出了全局变量。我稍后会和他一起工作

python