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Accepted
Alexsey Kr
Asked:2020-08-20 19:20:22 +0000 UTC2020-08-20 19:20:22 +0000 UTC

Python解析器

  • 772
import requests
from lxml import html


response = requests.get('https://www.youtube.com/results?search_query=gorrilaz&sp=CAE%253D')
parser_tree = html.fromstring(response.content)
content = parser_tree.xpath('//*[contains(@class, "yt-lockup-thumbnail")]/a[@href]')

print(content)
print(type(content[0]))

我正在尝试获取页面上的所有链接。答案为何而来

"元素 a 位于 0x7ff2295f80e8">

?

python

1 个回答

  1. Best Answer

    在变量中content你有类对象lxml.html.HtmlElement为了拉出链接，我们可以get('href')在每个这样的元素上调用一个方法：

    In [5]: type(content[0])
Out[5]: lxml.html.HtmlElement

In [6]: links = [el.get('href') for el in content]

In [7]: links
Out[7]: 
['/watch?v=CJV08IuDtG8',
 '/watch?v=gMAGskTN9SM',
 '/watch?v=_pr0kBvbuNc',
 '/watch?v=7tsPhlmnsuQ',
 '/watch?v=pM7_UnguPp0',
 '/watch?v=nP6qhrdfTjs',
 '/watch?v=DH6EYKihEd4',
 '/watch?v=JChkWu6XLjI',
 '/watch?v=qolRTEITF6s',
 '/watch?v=qH7y8yQ48dg',
 '/watch?v=8VYLHwxd-e0',
 '/watch?v=5LrAW-roUWk',
 '/watch?v=D4vEtnOIqNs',
 '/watch?v=3Scp7rlqQ2Y',
 '/watch?v=ZAFJSbduMqg',
 '/watch?v=FolC7vZl4G4',
 '/watch?v=JF4Cujp52Qc',
 '/watch?v=iUHVHILLTyo',
 '/watch?v=83FdYHkPNC0',
 '/watch?v=c72k6n0q13o']
    • 0

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