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主页 / user-319122

Alexsey Kr's questions

Martin Hope
Alexsey Kr
Asked: 2020-01-17 23:23:53 +0000 UTC

图片无法通过 {{ contact.contact_image.ur }} 加载

  • 1

问题是应用程序试图从链接中提取图像

/ref_pages/media/fbRostovay.jpg1.JPG

但它是可用的

/media/fbRostovay.jpg1.JPG

该应用程序自动添加

/ref_pages

如果我将 MEDIA_URL = '/media/' 中的路径更改为 MEDIA_URL = '/ref_pages/media/' 那么它可以工作,但是另一个应用程序无法获取图片

在另一个应用程序中,一切正常,我不明白我在哪里搞砸了,请告诉我,因为它可能是什么

模型.py

from __future__ import unicode_literals
from django.db import models


class Referer(models.Model):
    class Meta():
        db_table = "ref_pages_referer"

    ref_link = models.CharField(max_length=200)
    describe_link = models.TextField()
    free_test = models.BooleanField(default=True)
    personal_proxy = models.BooleanField(default=True)
    change_proxy = models.BooleanField(default=True)
    public = models.BooleanField(default=True)
    img = models.ImageField(default='img/q12.jpg')

    def __str__(self):
        return self.describe_link

视图.py

from django.core.paginator import Paginator
from django.shortcuts import get_object_or_404, render

from .models import Referer


def category(request):
    return render(request, 'ref_pages/category.html')

def support(request):
    contact_list = Referer.objects.all()
    paginator = Paginator(contact_list, 2)  # Show 25 contacts per page
    page = request.GET.get('page')
    contacts = paginator.get_page(page)
    return render(request, 'ref_pages/index.html', {'contacts': contacts})

网址.py

from django.urls import path

from . import views

app_name = 'ref_pages'

urlpatterns = [
    path('category', views.category, name='category'),
    path('', views.support, name='index'),
]

设置.py

STATIC_URL = '/static/'
STATIC_ROOT = os.path.join(BASE_DIR, 'poll/static') # добавил для отображения новой админки
STATICFILES_DIRS = (os.path.join(BASE_DIR, "static"),)

MEDIA_URL = '/media/'
MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
python
  • 2 个回答
  • 10 Views
Martin Hope
Alexsey Kr
Asked: 2020-10-18 15:37:16 +0000 UTC

读取文件时出现Python错误

  • 0

如果文件包含这种类型的行:

第一的

第二

那么一切都很好,但如果他们从

像这样的“@”例如@David,@masha,@sergey

然后出现错误

return codecs.charmap_decode(input,self.errors,decoding_table)[0] UnicodeDecodeError: 'charmap' codec can't decode byte 0x98 in position 2291:character maps to undefined>

我知道错误与编码有关,但我不明白要修复什么,以及在什么情况下(使用什么字符时)会出现这样的错误。

编码

ra = open("user_name", "r")
for i in ra:
  print(i)
python
  • 1 个回答
  • 10 Views
Martin Hope
Alexsey Kr
Asked: 2020-10-16 22:33:09 +0000 UTC

解释为什么函数返回 None

  • -1
x = 12
y = 21
deff = lambda *ar: print(*ar, sep=",")
print(deff(x,y))

为什么没有记录?

12.21

没有任何

python
  • 1 个回答
  • 10 Views
Martin Hope
Alexsey Kr
Asked: 2020-09-26 15:08:38 +0000 UTC

Android Studio 如何使用 adb 在启动时转到所需的步骤

  • 0

脚本启动时,此页面在模拟器中加载

desired_caps["appActivity"] = "com.viber.voip.AddFriendActivity"

经过一定的操作,需要返回到同一页面,如何快速做到这一点?使应用程序在正确的位置立即加载,就像在启动时一样,您不必长时间单击。

像这样尝试:

adb shell am start -a com.viber.voip.AddFriendActivity"

不工作!

python-3.x
  • 1 个回答
  • 10 Views
Martin Hope
Alexsey Kr
Asked: 2020-09-24 16:15:43 +0000 UTC

Android Studio 获取下载到模拟器的文件

  • 0

我正在模拟器中下载文件(联系人),但我无法“拿起它们”。我不明白如何设置下载路径或如何从模拟器中获取文件。

python
  • 1 个回答
  • 10 Views
Martin Hope
Alexsey Kr
Asked: 2020-08-23 21:35:48 +0000 UTC

Python电报机器人在提交后获取电话号码

  • 0
        @bot.message_handler(commands=["geophone"])
        def geophone(message):
            keyboard = types.ReplyKeyboardMarkup(row_width=1, resize_keyboard=True)
            button_phone = types.KeyboardButton(text="Отправить номер телефона", request_contact=True)
            button_geo = types.KeyboardButton(text="Отправить местоположение", request_location=True)
            keyboard.add(button_phone, button_geo)
            bot.send_message(message.chat.id, "Отправь мне свой номер", reply_markup=keyboard)

电话号码存储在哪里?如果用户同意并发送给我,我如何获得电话号码?

python
  • 2 个回答
  • 10 Views
Martin Hope
Alexsey Kr
Asked: 2020-08-20 19:20:22 +0000 UTC

Python解析器

  • 1
import requests
from lxml import html


response = requests.get('https://www.youtube.com/results?search_query=gorrilaz&sp=CAE%253D')
parser_tree = html.fromstring(response.content)
content = parser_tree.xpath('//*[contains(@class, "yt-lockup-thumbnail")]/a[@href]')

print(content)
print(type(content[0]))

我正在尝试获取页面上的所有链接。答案为何而来

"元素 a 位于 0x7ff2295f80e8">

?

python
  • 1 个回答
  • 10 Views
Martin Hope
Alexsey Kr
Asked: 2020-07-31 18:31:18 +0000 UTC

Python Selenium 获取整个页面代码以记录或归档

  • 0

这是我的代码,如何正确获取整个页面的代码?然后将其保存到文件中?

from selenium import webdriver
import time
driver = webdriver.Chrome()
driver.set_window_position(0, 0)
driver.set_window_size(1920, 1080)
driver.get("https://google.com/")
time.sleep(2)

main_page = driver.find_element_by_tag_name("html")

print(main_page)

print 给出以下信息

selenium.webdriver.remote.webelement.WebElement (session="e97b70608252184611ceabc87f774282", element="bd9f8eef-fe4f-4371-85ba-9d6fc98e8abc"

python
  • 2 个回答
  • 10 Views
Martin Hope
Alexsey Kr
Asked: 2020-07-30 18:10:35 +0000 UTC

Python selenium 加载 cookie

  • 1

我从另一个程序中提取了 cookie,它们可以加载到 Python/selenium 中吗?如果是这样,怎么做?

{"cookies":[{"creation":{"day_of_month":"22","day_of_week":"1","hour":"8","millisecond":"407","minute":"27 ","month":"4","second":"8","year":"2019"},"domain":".google.com","expires":{"day_of_month":"20" ,"day_of_week":"4","hour":"8","millisecond":"959","minute":"38","month":"8","second":"19","年":"2020"},"has_expires":"1","httponly":"0","last_access":{"day_of_month":"22","day_of_week":"1","小时":"8","毫秒":"258","分钟":"27","月":"4","秒":"28","年":"2019"},"名称":"SID","path":"/","secure":"0","value":"YwZsDrqtUIbbr_ytVK3W403nQdMj_DbSCrGG_YJpcd3GU98JiwMfABhsouVY6vOwumn3Lg."},{"creation":{"day_of_month":"22","day_of_week": "1","小时":"8","毫秒":"407","分钟":"27","月":"4","秒":"8","年":"2019 "},"domain":".google.com","expires":{"day_of_month":"22","day_of_week":"1","小时":"8","毫秒":"770","分钟":"28","月":"4","秒":"37","年":"2019"},"名称":"SIDCC","path":"/","secure":"0","value":"AN0-TYtaRheNesUAP9wJacTdOACPZXT3ReVry3G35yeCN_86gZdXQqTg4a0kyTs90_5tJHEo"}]}

python
  • 1 个回答
  • 10 Views
Martin Hope
Alexsey Kr
Asked: 2020-07-10 17:54:18 +0000 UTC

Django / SQL / 验证

  • 0

告诉我如何正确进行检查,我需要检查数据库中是否存在这样的一对(ip和user_agent),如果没有,则添加

视图.py

def all(request):
x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
if x_forwarded_for:
    ip = x_forwarded_for.split(',')[0]
else:
    ip = request.META.get('REMOTE_ADDR')
    user_agent = request.META.get('HTTP_USER_AGENT')
    name_host = request.META.get('SERVER_PORT')
    method = request.META.get('REQUEST_METHOD')


data = {"ip": ip,"user_agent": user_agent,"name_host": name_host,"method": method }
return render(request, 'poll/all.html', context=data)

模型.py

class Unique_set(models.Model):
     UserAgent = models.TextField()
     IP_user = models.CharField(max_length=50)

     def __str__(self):
         return self.IP_user
sql
  • 1 个回答
  • 10 Views
Martin Hope
Alexsey Kr
Asked: 2020-07-08 15:27:58 +0000 UTC

Python / django / 获取访问者 ip

  • -3

你能告诉我如何获取用户的IP吗?

python
  • 1 个回答
  • 10 Views
Martin Hope
Alexsey Kr
Asked: 2020-06-14 21:24:59 +0000 UTC

Python/django/分页

  • 0
<div class="container text-center">

        {% for contact in contacts %}
            <h6>имя пользователя:{{ contact.name_persone }}</h6>
            <h4><a href="/support?page/{{ contact.id }}/">{{ contact.phone_persone }}</a></h4>
            <p>{{ article.article_text }}</p>
            <p><a href="/support?page/{{ contact.id }}/"><img src="{% static hero.jpg %}" width="25px" height="25px"></a>{{ contact.phone_persone }}</p>
    {% endfor %}

    <ul class="pagination">

            {% if contacts.has_previous %}
                <li><a href="?page=1">&laquo; first</a></li>
               <li> <a href="?page={{ contacts.previous_page_number }}">previous</a></li>
            {% endif %}
             {% for page in contacts.paginator.page_range %}
                        {% if page == contacts.number %}
                            <li class="current"><a href="/support?page/{{ page }}/">{{ page }}</a></li>
                        {% else %}
                            <li><a href="/support?page/{{ page }}/">{{ page }}</a></li>
                        {% endif %}
            {% endfor %}
            {% if contacts.has_next %}
                <li><a href="?page={{ contacts.next_page_number }}">next</a></li>
                <li><a href="?page={{ contacts.paginator.num_pages }}">last &raquo;</a></li>
            {% endif %}

    </ul></div>

我的分页的问题是,如果你点击分页页码,页面上的信息并没有更新,尽管 URL 本身发生了变化(发生了分页)。由于某种原因,信息没有被提取。但是,如果我单击“下一步”,那么一切正常。告诉我出了什么事?也许有人会看到更多错误,我将不胜感激!

python
  • 1 个回答
  • 10 Views

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