如何不通过 ID 绑定多对多

2 个实体 House 和 City 以及数据库的屏幕截图。现在我意识到我没有完全正确地连接它，因为当用户提出请求时，他需要输入城市的号码，而不是名称，这是不正确的。如何正确绑定，以便在发生请求时将城市名称添加到 House 并链接到 City？

城市

@Data
@Entity
@JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
@Table(name = "city", schema = "public")
public class City {

@Id
@GeneratedValue(strategy= GenerationType.IDENTITY)
@Column(name = "id")
private Long id;

@OneToMany(cascade = {CascadeType.DETACH, CascadeType.MERGE, CascadeType.PERSIST,
        CascadeType.REFRESH
}, mappedBy = "city")
@ToString.Exclude
@EqualsAndHashCode.Exclude
@JsonIgnore
private Set<House> house;

@Column(name = "id_region", nullable = false)
private Integer id_region;
@Column(name = "name", nullable = false)
private String name;
}

房子

@Data
@Entity
@JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
@Table (name = "house", schema = "public")
public class House {

    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    @Column(name = "id")
    private Long id;

    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "city_id")
    private City city;

    @OneToMany(mappedBy = "house")
    private Set<Contract> contract;

    @Column(name = "id_landlord", nullable = false)
    private Long id_landlord;
    @Column(name = "outside", nullable = false)
    private String outside;
    @Column(name = "rooms", nullable = false)
    private Integer rooms;
    @Column(name = "price", nullable = false)
    private Double price;
    @Column(name = "description", nullable = false)
    private String description;
    @Enumerated(value = EnumType.STRING)
    @Column(name = "status")
    private Status status;
}