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андрей гривкин
Asked:2020-01-07 17:52:40 +0000 UTC2020-01-07 17:52:40 +0000 UTC

从文件中获取字符串并将其转换为 int Python 类型

  • 772

该函数从 users.txt 文件中读取用户的登录名（那里总是只有一个登录名），然后查找相同的 inprogress.txt，如果找到，则需要将登录名后面的行替换为再一个，从 1 到 2，从 2 等。.d。是班级编号。如果是第一次输入登录名，那么只需将其写入progress后跟1。问题是我不明白如何从文件中获取带有数字的这一行，将其转换为int，加1，然后把它写到同一个地方。或许答案是显而易见的，但我对 Python 才熟悉几天，还是不太了解。提前致谢

with open('users.txt', 'r') as f:
line = f.readline()
f.close()
with open('progress.txt', 'r') as k:
while True:
    global uroka_in
    lines = k.readline()
    if line == lines.rstrip():
        uroka_in = int(k.readline().rstrip())
        urokb_in = uroka_in + 1
        uroka_str = str(uroka_in)
        urokb_str = str(urokb_in)
        lines.replace(uroka_str, urokb_str)
        k.close()
        break
    if not lines:
        k.close()
        global urokb_in
        urokb_in = 1
        with open('progress.txt', 'a') as j:
            j.write(line)
            j.write('\n')
            j.write(str(urokb_in))
            j.write('\n')
            j.close()
            break

示例 progress.txt 文件：

username1
1
username2
1
username3
1

编辑：

def user():
with open('users.txt') as k:
    user = k.readline()
    k.close()
def increment_counter(user, 'progress.txt'):
    with open('progress.txt', 'r') as f:
     data = yaml.safe_load(f.read())
    data[user] += 1
    with open('progress.txt', 'w') as f:
    yaml.dump(data, f, indent=2, default_flow_style=False)
python

2 个回答

  1. 试试这样：

    import yaml   #  требует установленного модуля `yaml`: pip install pyyaml

def get_user(filename=r'/path/to/users.txt'):
    with open(filename) as f:
        return f.readline()

def increment_counter(user, filename):
    with open(filename, 'r') as f:
        data = yaml.safe_load(f.read())
    data[user] += 1
    with open(filename, 'w') as f:
        yaml.dump(data, f, indent=2, default_flow_style=False)

    使用示例：

    increment_counter(get_user(r'/path/to/users.txt'), r'/path/to/progress.yml')

    progress.yml函数调用之前的示例 YAML 文件 ( )：

    username1: 1
username2: 1
username3: 1

    "progress.yml"通话后内容increment_counter('username3', r'/path/to/progress.yml')：

    username1: 1
username2: 1
username3: 2

    纯文本文件的功能（如问题所示）

    def increment_counter(user, filename):
    with open(filename, 'r') as f:
        data = f.read()
    with open(filename, 'w') as f:
        pat = r'(' + user + r'[\r\n]+)(\d+)'
        m = re.search(pat, data)
        if m:
            s = m.group(1)
            s += str(int(m.group(2)) + 1)
            new = re.sub(pat, s, data)
            f.write(new)
        else:
            f.write(data)

    使用示例：

    increment_counter('username3', r'/path/to/progress.txt')

    PS 我推荐使用 YAML 来存储用户数据

    • 1
  2. Best Answer
    import json

def progress():
    #p_dict = eval(open('progress.txt').read())
    p_dict = json.load(open('progress.txt'))
    user = next(filter(bool, map(str.strip, open('users.txt'))))

    if user in p_dict:
        p_dict[user] += 1
    else:
        p_dict[user] = 1

    with open('progress.txt', 'w') as f:
        json.dump(p_dict, f, indent=0, sort_keys=True)

    例如'progress.txt'

    {
"user0": 1,
"user1": 4,
"user3": 2
}

    空的“progress.txt”最初应该包含一行：{}

    另一种选择，正如问题作者想要的那样：

    def progress():
    iter_lines = filter(bool, map(str.strip, open('progress.txt')))
    p_dict = {k: int(v) for k, v in zip(iter_lines, iter_lines)}
    user = next(filter(bool, map(str.strip, open('users.txt'))))

    if user in p_dict:
        p_dict[user] += 1
    else:
        p_dict[user] = 1

    with open('progress.txt', 'w') as f:
        f.write('\n'.join('{}\n{}'.format(k, p_dict[k]) for k in p_dict))

    return user, p_dict

    例如'progress.txt'

    user0
1
user1
4
user3
2
    • 1

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