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Сергей
Asked:2020-05-06 03:39:58 +0000 UTC2020-05-06 03:39:58 +0000 UTC

模型参数通过浏览器线获取

  • 772

Index有控制器方法files。

    [HttpGet]
    public ActionResult Index()
    {
        return View();
    }

    [HttpPost]
    public ActionResult Index(UploadModel ResultModel)
    {
        if (ResultModel.FileId != null)
        {
            ViewBag.UploadResutl = "File Uploaded Successful!";
            ViewBag.UploadLink = $"File Link :: {ResultModel.FileId}";
            ViewBag.UploadPassword = $"File Password :: {ResultModel.Password}";
        }
        else
            ViewBag.UploadResutl = ResultModel.Result;
        return View();
    }

这些字段是文件上传和重定向成功后UploadModel 显示的私有数据：View

表现 ：

<div> 
    <h3>Выберите файл для загрузки</h3>
    @using (Html.BeginForm("upload", "files", FormMethod.Post, new { enctype = "multipart/form-data" }))
    {
        <input type="file" name="upload" value="Открыть" /><br>
        <input type="submit" value="Загрузить" />
    }
</div>

上传文件 ：

public async Task<ActionResult> upload(HttpPostedFileBase upload)
{
    ...
    return RedirectToAction("Index", ResultModel);
}

但是，另外它们显示在浏览器和历史栏中，这不再好。如何传递给Index模型，使其不会显示在浏览器行中？

在此处输入图像描述

c#

1 个回答

  1. Best Answer

    模型

    public class UploadViewModel
{
    public string UploadResult {get;set;}
    public string UploadLink {get;set;}
    public string UploadPassword {get;set;}
    public HttpFilePostedBase File {get;set;}
    public bool HasUploaded {get;set;}
}

    根据GET要求，加载页面：

    [HttpGet]
public ActionResult Index()
{
    return View(new UploadViewModel());
}

    看法

    @model UploadViewModel

<div> 
    <h3>Выберите файл для загрузки</h3>
    @using (Html.BeginForm("index", "files", FormMethod.Post, new { enctype = "multipart/form-data" }))
    {
        <input type="file" name="@Html.NameFor(x => x.File)" value="Открыть" /><br>
        <input type="submit" value="Загрузить" />
    }
</div>

@if (model.HasUploaded)
{
    <div>@model.UploadResult</div>
    <div>Link: @model.UploadLink</div>
    <div>Password: @model.UploadPassword</div>
}

    POST方法

    [HttpPost]
public ActionResult Index(UploadViewModel model)
{
    if (model.File != null)
    {
        // upload file


        model.UploadResult = .....
    }

    return View(model)
}
    • 1

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