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Антон Лялин
Asked:2020-08-03 17:51:29 +0000 UTC2020-08-03 17:51:29 +0000 UTC

如何使用改造解析嵌套数组？

  • 772

有 json，它有一个嵌套数组payments，如何使用它来解析它retrofit？ 

"credits": [

  {

    "name": "Кредит Выгодный",

    "contractNumber": 4666888,

    "openedDate": "2018-02-09T21:58:57+00:00",

    "nextPaymentDate": "2018-05-11T05:58:57+00:00",

    "nextPaymentAmount": 8900,

    "percent": 15.4,

    "amount": 125000,

    "currency": "rur",

    "status":"active",

    "payments": [

      {

        "paymentDate": "2018-03-09T21:58:57+00:00",

        "paymentAmount": 3400,

        "status": "paid"

      },

      {

        "paymentDate": "2018-04-09T21:58:57+00:00",

        "paymentAmount": 3700,

        "status": "paid"

      },

      {

        "paymentDate": "2018-05-09T21:58:57+00:00",

        "paymentAmount": 4400,

        "status": "skipped"

      },

      {

        "paymentDate": "2018-06-09T21:58:57+00:00",

        "paymentAmount": 4400,

        "status": "future"

      }

    ]

  },

对于我credits创建class Credits { //данные (id, name, и т.д.)}，如果我创建相同的payments，那么它很简单null或发生错误

java.lang.IllegalStateException: 
Expected BEGIN OBJECT but was BEGIN_ARRAY at line 4 column 14 path $.result

public abstract class BaseProducts {

@NonNull
@SerializedName("name")
private String name;
@NonNull
@SerializedName("openedDate")
private Date openedDate;
@SerializedName("amount")
private Double amount;
@NonNull
@SerializedName("currency")
private String currency;
@Nullable
@SerializedName("status")
private String status;

public class Credits extends BaseProducts {

@SerializedName("contractNumber")
private Long contractNumber;
@NonNull
@SerializedName("nextPaymentDate")
private Date nextPaymentDate;
@SerializedName("nextPaymentAmount")
private Double nextPaymentAmount;
@NonNull
@SerializedName("percent")
private Double percent;
}

public class Payments extends BaseProducts {

@NonNull
@SerializedName("paymentDate")
private Date paymentDate;
@SerializedName("paymentAmount")
private Double paymentAmount;
}

public class ApiResponse<T> {

@SerializedName("resultCode")
private int resultCode;
@SerializedName("error")
private String error;
@SerializedName("result")
private T result;
}

public class ProductResponse {
@SerializedName("credits")
private List<Credits> credits = null;
@SerializedName("payments")
private List<Payments> payments = null;
}

public interface BankApi {
@GET(EnumsUrl.URL_PRODUCTS)
Single<ApiResponse<ProductResponse>> getProductsSingle();
}
android

3 个回答

  1. 一般来说，你需要使用JsonPojo，它会构建正确的结构

    • 1

  2. 您需要使用生成器制作一个普通的 POJO，然后可能使用句柄对其进行编辑。然后只需用注释指示您需要绘制的内容。要访问嵌套数组payments，您需要在其中创建嵌套类"credits"

    实际上，这里 是同样的问题，同样的问题。事实上，没有什么复杂的。

    • 1
  3. Best Answer

    您只需要将 List 从 ProductResponse 类转移到 Credits 类（即使模型与 JSON 本身的结构保持一致）

    产品响应类：

    public class ProductResponse {
    @SerializedName("credits")
    private List<Credits> credits = null;
}

    课程学分：

    public class Credits extends BaseProducts {

    @SerializedName("contractNumber")
    private Long contractNumber;
    @NonNull
    @SerializedName("nextPaymentDate")
    private Date nextPaymentDate;
    @SerializedName("nextPaymentAmount")
    private Double nextPaymentAmount;
    @NonNull
    @SerializedName("percent")
    private Double percent;
    @SerializedName("payments")
    private List<Payments> payments = null;
}

    一般来说，POJO最好不要使用继承

    • 1

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