主页 / 问题 / 878955
Accepted
jokop
Asked:2020-09-08 23:38:34 +0800 CST2020-09-08 23:38:34 +0800 CST

将 int 对象转换为列表

  • 772

有一个循环，其中的cache值是从中选择的：

  cache = [[(0, 0), (1, 0), (2, 0)],
     [(0, 0), (1, 0), (0, 0)],
     [(0, 0), (1, 0), (1, 1)],
     [(0, 0), (1, 0), (1, -1)],
     [(0, 0), (-1, 0), (0, 0)],
     [(0, 0), (-1, 0), (-2, 0)],
     [(0, 0), (-1, 0), (-1, 1)],
     [(0, 0), (-1, 0), (-1, -1)],
     [(0, 0), (0, 1), (1, 1)],
     [(0, 0), (0, 1), (-1, 1)],
     [(0, 0), (0, 1), (0, 2)],
     [(0, 0), (0, 1), (0, 0)],
     [(0, 0), (0, -1), (1, -1)],
     [(0, 0), (0, -1), (-1, -1)],
     [(0, 0), (0, -1), (0, 0)],
     [(0, 0), (0, -1), (0, -2)]]

循环本身

for x in range (len(cache)):
    for e in range(len(cache[x])):
        q,z = cache[x][e]
        print(q)

如何从循环中每次迭代获得的 q 中获取列表？ map(int,str(q))不能应用，因为有负q

python

1 个回答

  1. Best Answer
     (j for i in map(lambda x: tuple(zip(*x))[0], cache) for j in i)
    • 3

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