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JDo
Asked:2020-09-20 22:42:35 +0000 UTC2020-09-20 22:42:35 +0000 UTC

访问 C# 模型中所有字典的值

  • 772

我想尝试达到包装在数据模型中的字典的值，但最终我得到的不是我需要的。需要使用 GetAll() 方法一次从所有字典中获取数据；数据模型：

public class Model
{
    public Dictionary<int, string> FirstDepartment { get; set; }
    public Dictionary<int, string> SecondDepartment { get; set; }
    public Dictionary<int, string> ThirdtDepartment { get; set; }
}

管理器或存储库

public class Manager
{
    private Model _model;
    private List<Model> _lst;

    public Manager()
    {
        _lst = new List<Model>();

        _model = new Model()
        {
            FirstDepartment = new Dictionary<int, string>(),
            SecondDepartment = new Dictionary<int, string>(),
            ThirdtDepartment = new Dictionary<int, string>()
        };

        _model.FirstDepartment.Add(1, "Вася");
        _model.FirstDepartment.Add(2, "Петя");
        _model.SecondDepartment.Add(3, "Катя");
        _model.SecondDepartment.Add(4, "Иван");
        _lst.Add(_model);
    }

    public List<Model> GetAll() => _lst;

}

主要的：

static void Main(string[] args)
{
    Console.WriteLine("=======================================");

    Manager mg = new Manager();

    foreach (var item in mg.GetAll())
    {
        Console.WriteLine($"++++ {item} ++++");
    }

    Console.WriteLine();

    Console.ReadKey();
}

我得到以下信息：

在此处输入图像描述

怎样才能正确打包，然后遍历整个模型的所有值（所有字典的Values）。

c#

1 个回答

  1. Best Answer

    字典值连接：

    public class Model
{
    public Dictionary<int, string> FirstDepartment { get; set; }
    public Dictionary<int, string> SecondDepartment { get; set; }
    public Dictionary<int, string> ThirdtDepartment { get; set; }
}

public class Manager
{
    private Model _model;

    public Manager()
    {
        _model = new Model()
        {
            FirstDepartment = new Dictionary<int, string>(),
            SecondDepartment = new Dictionary<int, string>(),
            ThirdtDepartment = new Dictionary<int, string>()
        };

        _model.FirstDepartment.Add(1, "Вася");
        _model.FirstDepartment.Add(2, "Петя");
        _model.SecondDepartment.Add(3, "Катя");
        _model.SecondDepartment.Add(4, "Иван");     
    }

    public List<string> GetAll() => _model.FirstDepartment.Values
                                        .Concat(_model.SecondDepartment.Values)
                                        .Concat(_model.ThirdtDepartment.Values)
                                        .ToList();

}

    考试

    Console.WriteLine("=======================================");

Manager mg = new Manager();

foreach (var item in mg.GetAll())
{
    Console.WriteLine($"++++ {item} ++++");
}

Console.WriteLine();

    结论

    =======================================
++++ Вася ++++
++++ Петя ++++
++++ Катя ++++
++++ Иван ++++
    • 2

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